get the partial match string using java regex pattern

Question

I have a pattern like below

Sentence = "@502348@502002662[000861@10";
Pattern = "^@(\\d{6})@*(\\d{9})\\[(\\d{6})@(\\d{2})";

Matcher regexMatcher = regexPattern.matcher(Sentence);
    if (regexMatcher.find()) 
      str1= regexMatcher.group(1);
      str2 = regexMatcher.group(2);
      str3 = regexMatcher.group(3);
      str4 = regexMatcher.group(4);
    }

The above one works fine if the sentence is appropriately matches. But my requirement is , the partial result should be returned in case the pattern is not matches appropriately.

For example if Sentence = "@114142@000017000[" then i want to get the str1 and str2.

Thanks

anubhava · Accepted Answer · 2014-07-29 18:10:37Z

1

You can use make last part optional:

^@(\\d{6})@*(\\d{9})(?:\\[(\\d{6})@(\\d{2}))?

RegEx Demo

answered Jul 29, 2014 at 18:10

anubhava

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Pshemo · Accepted Answer · 2014-07-29 18:14:45Z

1

I am not sure if this is what you are looking for but you can try something like

^@(\\d{6})(?:@*(\\d{9})(?:\\[(\\d{6})(?:@(\\d{2}))?)?)?

This makes

@xxxxxx@xxxxxxxxx[xxxxxx@xx
       ^^^^^^^^^^^^^^^^^^^^ - optional
                 ^^^^^^^^^^ - optional
                         ^^ - optional

answered Jul 29, 2014 at 18:14

Pshemo

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