Shell script Error : Conditional biinary operator expected

Question

I am getting the error "Conditional binary operator expected in the following script.

if [[ $LOCALE -eq 'US' ]]; then
RWLOGGROUPNAME=/US/Live/access-log
DPXLOGGROUPNAME=/US/Live/access-log
END_POINT=https://us.ginger.com
fi

if [[ $LOCALE -eq 'DE' || $LOCALE -eq 'FR' || $LOCALE -eq 'IT' ||  $LOCALE -eq 'UK' ]]; then
RWLOGGROUPNAME=$LOCALE/Live/access-log
DPXLOGGROUPNAME=$LOCALE/Prod/access_log
END_POINT=https://eu.ginger.com
fi

Can some one tell me what is going wrong here. I am taking locale from command line and have put it in quotes as it's a string.The first if works fine but the next one does not.

anubhava · Accepted Answer · 2014-07-30 10:25:23Z

1

-eq is used for integer comparison only, moreover you are using eq at few places instead of -eq.

Make it:

if [ "$LOCALE" = "DE" -o "$LOCALE" = "FR" -o "$LOCALE" = "IT" -o "$LOCALE" = "UK" ]; then

edited Jul 30, 2014 at 10:25

answered Jul 30, 2014 at 10:20

anubhava

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2 Comments

user2890683 Over a year ago

I have it in code . It somehow got removed while posting the issue here :)

anubhava Over a year ago

ok check updated answer now. You cannot use -eq for string comparison.

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