How to add a node to XML with XMLBeans XmlObject

Question

My goal is to take an XML string and parse it with XMLBeans XmlObject and add a few child nodes.

Here's an example document (xmlString),

<?xml version="1.0"?>
<rootNode>
 <person>
  <emailAddress>[email protected]</emailAddress>
 </person>
</rootNode>

Here's the way I'd like the XML document to be after adding some nodes,

<?xml version="1.0"?>
<rootNode>
 <person>
  <emailAddress>[email protected]</emailAddress>
  <phoneNumbers>
   <home>555-555-5555</home>
   <work>555-555-5555</work>
  <phoneNumbers>
 </person>
</rootNode>

Basically, just adding the <phoneNumbers/> node with two child nodes <home/> and <work/>.

This is as far as I've gotten,

XmlObject xml = XmlObject.Factory.parse(xmlString);

Thank you

Kevin Krouse · Accepted Answer · 2011-05-06 18:50:24Z

Here is an example of using the XmlCursor to insert new elements. You can also get a DOM Node for an XmlObject and using those APIs.

import org.apache.xmlbeans.*;

/**
 * Adding nodes to xml using XmlCursor.
 * @see http://xmlbeans.apache.org/docs/2.4.0/guide/conNavigatingXMLwithCursors.html
 * @see http://xmlbeans.apache.org/docs/2.4.0/reference/org/apache/xmlbeans/XmlCursor.html
 */
public class AddNodes
{
    public static final String xml =
    "<rootNode>\n" +
    "  <person>\n" +
    "    <emailAddress>[email protected]</emailAddress>\n" +
    "  </person>\n" +
    "</rootNode>\n";

    public static XmlOptions saveOptions = new XmlOptions().setSavePrettyPrint().setSavePrettyPrintIndent(2);

    public static void main(String[] args) throws XmlException
    {
        XmlObject xobj = XmlObject.Factory.parse(xml);
        XmlCursor cur = null;
        try
        {
            cur = xobj.newCursor();
            // We could use the convenient xobj.selectPath() or cur.selectPath()
            // to position the cursor on the <person> element, but let's use the
            // cursor's toChild() instead.
            cur.toChild("rootNode");
            cur.toChild("person");
            // Move to </person> end element.
            cur.toEndToken();
            // Start a new <phoneNumbers> element
            cur.beginElement("phoneNumbers");
            // Start a new <work> element
            cur.beginElement("work");
            cur.insertChars("555-555-5555");
            // Move past the </work> end element
            cur.toNextToken();
            // Or insert a new element the easy way in one step...
            cur.insertElementWithText("home", "555-555-5555");
        }
        finally
        {
            if (cur != null) cur.dispose();
        }

        System.out.println(xobj.xmlText(saveOptions));
    }

}

MarcoS · Accepted Answer · 2011-05-06 20:08:00Z

3

XMLBeans seems like a hassle, here's a solution using XOM:

import nu.xom.*;

Builder = new Builder();
Document doc = builder.build(new java.io.StringBufferInputStream(inputXml));
Nodes nodes = doc.query("person");
Element homePhone = new Element("home");
homePhone.addChild(new Text("555-555-5555"));
Element workPhone = new Element("work");
workPhone.addChild(new Text("555-555-5555"));
Element phoneNumbers = new Element("phoneNumbers");
phoneNumbers.addChild(homePhone);
phoneNumbers.addChild(workPhone);
nodes[0].addChild(phoneNumbers);
System.out.println(doc.toXML()); // should print modified xml

edited May 6, 2011 at 20:08

MarcoS

13.6k7 gold badges45 silver badges64 bronze badges

answered Apr 27, 2010 at 20:38

Nathan Hughes

96.7k21 gold badges193 silver badges288 bronze badges

2 Comments

MarcoS Over a year ago

very interesting: I did know XOM: I looks very easy to use! Will keep an eye on it

wsams Over a year ago

Yeah, I like this too - never used XOM.

Kannan Ekanath · Accepted Answer · 2010-03-26 12:03:14Z

0

It may be a little difficult to manipulate the objects using just the XmlObject interface. Have you considered generating the XMLBEANS java objects from this xml?

If you don't have XSD for this schema you can generate it using XMLSPY or some such tools.

If you just want XML manipulation (i.e, adding nodes) you could try some other APIs like jdom or xstream or some such thing.

answered Mar 26, 2010 at 12:03

Kannan Ekanath

17.8k22 gold badges83 silver badges106 bronze badges

8 Comments

wsams Over a year ago

I haven't tried generating XMLBEANS java objects. Any pointers on where to look or start? I'm pretty new to parsing XML with Java. I'll take a look at jdom and xstream as well.

Kannan Ekanath Over a year ago

It will definitely help if you define clearly what your end goal is. Is it "Adding a few nodes to an existing xml and outputting xml" ?

Kannan Ekanath Over a year ago

Check this link if you want simple manipulation exampledepot.com/egs/org.w3c.dom/AddText.html

wsams Over a year ago

Oh sorry, yeah I'd like to take the xml string as input and output the new xml with nodes added as a string. So the input should be xml and the output should be xml with new nodes added.

Kannan Ekanath Over a year ago

So these links exampledepot.com/egs/org.w3c.dom/AddNode.html and exampledepot.com/egs/org.w3c.dom/AddText.html do not solve your problem ?

|

Andrew Barber · Accepted Answer · 2012-10-03 16:00:20Z

0

Method getDomNode() gives you access to the underlying W3C DOM Node. Then you can append childs using W3C Document interface.

edited Oct 3, 2012 at 16:00

Andrew Barber

40.3k20 gold badges97 silver badges124 bronze badges

answered Aug 1, 2012 at 12:10

jseba

1

Collectives™ on Stack Overflow

How to add a node to XML with XMLBeans XmlObject

4 Answers 4

Comments

2 Comments

8 Comments

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

4 Answers 4

Comments

2 Comments

8 Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related