Try - Catch Exception Java - Eclipse

Question

Well I want to use this try/catch in Java using the Execption in a program. Basically the program is aim to get the number/ amount of a certain product and it calculates its price and discount.

I want the txtAmount which is supposed to receive only numbers does not crash if put letters here is part of the code. Just a simple solution

public static String modelo, obsequio = null, resolucion = null;
    public static int amount, numgift = 0, resolution = 0;
    public static double amountourchase = 0, idiscount = 0, itopayr = 0, discount = 0, price = 0;

    protected void actionPerformedBtnSell(ActionEvent arg0) {
        inData();
        calculateDiscount();
        prrocessPurchase();
        Results();
    }

    void indata(){
        model = cboModelo.getSelectedItem().toString();
        amount = Integer.parseInt(txtCantidad.getText());
    }

Dan Dosch · Accepted Answer · 2014-08-08 23:06:55Z

1

void indata() {
    model = cboModelo.getSelectedItem().toString();
    try {
        amount = Integer.parseInt(txtCantidad.getText());
    } catch (NumberFormatException e) {
        // Handle it here
    }
}

answered Aug 8, 2014 at 23:06

Dan Dosch

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2 Comments

axisrod09 Over a year ago

what about this example to use in the code above int readNumber (){ int num; try { num = Integer.parseInt(txtNumero.getText()); } catch (Exception e) { num = -1 ; return num; { . Is it possible to implement in the code abovve

axisrod09 Over a year ago

I was just finishing typing this is an example apart

Kick Buttowski · Accepted Answer · 2014-08-09 02:15:55Z

0

Code:

try {
        double d = Double.parseDouble(your input is here);
         or
        int i =  Integer.parseInt(your input is here);
    }
    catch (NumberFormatException e) {
         System.out.print(e);

    }

Note: try to work on this I think the code in below is the one that you are looking for.

Code:

public static void main(String[] args) {
        JFrame f = new JFrame("Demo");
        f.setLayout(new FlowLayout());
        f.setSize(300, 200);
        f.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
        f.setLocationRelativeTo(null);
        JLabel label = new JLabel("enter your number: ");
        JTextField userText = new JTextField(6);
        JButton button = new JButton("OK");
        JLabel label1 = new JLabel();

        button.addActionListener(new ActionListener() {
            @Override
            public void actionPerformed(ActionEvent ae) {
                try {
                    int i = Integer.parseInt(userText.getText());
                    label1.setText(Integer.toString(i));
                } catch (NumberFormatException e) {
                    JOptionPane.showMessageDialog(f,
                            "Input integer number ",
                            "NumberFormatException",
                            JOptionPane.ERROR_MESSAGE);
                    userText.setText("");
                }
            }
        });

        f.add(label);
        f.add(userText);
        f.add(button);
        f.add(label1);
        f.setVisible(true);
    }

Note : you should define your amount and other variables in type double to be more precise

edited Aug 9, 2014 at 2:15

answered Aug 8, 2014 at 23:07

Kick Buttowski

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4 Comments

axisrod09 Over a year ago

what about this new example to use in the code above int readNumber (){ int num; try { num = Integer.parseInt(txtNumero.getText()); } catch (Exception e) { num = -1 ; return num; { . Is it possible to implement in the code above?

Kick Buttowski Over a year ago

let me see what you try to say?

Kick Buttowski Over a year ago

what do you try to accomplish? cuz when you are in catch vlock and your return something. everything is gone. do you wanna ask the person to be in loop till he or she put the right format?

axisrod09 Over a year ago

yes because if the person continue putting a letter put a number

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