python regex to display text in parenthesis

Question

I did a coding to get to print ext inside (" and within ") but i get the errors.

I mean ,if i have text: hello everyone("Can you see"), then it has to print as Can you see

My coding:

>>> import re
>>> s = "<_io.TextIOWrapper ('C:/Python34/abcd.txt') mode='w' encoding='cp1252'>"
>>> m = re.search(r"(?<=\('\=\')[^\']*", s)
>>> m.group()

Traceback (most recent call last):
  File "<pyshell#6>", line 1, in <module>
    m.group()
AttributeError: 'NoneType' object has no attribute 'group'

Your description says you need to find (", but your code has (' instead. Should you be looking for one or the other, or both? — TheSoundDefense
– TheSoundDefense, Commented Aug 10, 2014 at 3:42
@TheSoundDefense yes my description was unmentioned and i need to display for both! — user3914506
– user3914506, Commented Aug 10, 2014 at 3:51

hjpotter92 · Accepted Answer · 2014-08-10 03:55:26Z

1

Modify your lookbehind a little:

(?<=\(')[^']*

and you'll have the following result:

>>> m = re.search( r"(?<=\(')[^']*", s)
>>> m.group()
'C:/Python34/abcd.txt'

To be able to match both ' and " as you mention in the comment, you'd need to create another capture group (for back referencing):

(?<=\((['"]))(.*?)\1

and thus:

>>> m = re.search( r"(?<=\(([\"']))(.*?)\1", s)
>>> m.group()
"C:/Python34/abcd.txt'"
>>> m.group(1)
"'"
>>> m.group(2)
'C:/Python34/abcd.txt'

edited Aug 10, 2014 at 3:55

answered Aug 10, 2014 at 3:47

hjpotter92

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1 Comment

user3914506 Over a year ago

how can i use it for both (" ") and (' ') ?,and i only need to print the text without codes!

khampson · Accepted Answer · 2014-08-10 03:47:39Z

1

Try something like this, which will use either single or double quotes. The group(1) gives the inner string. This regex escapes the outer parens so they don't represent a grouping.

>>> m = re.search(r"\(['\"](.+)?['\"]\)", s)
>>> m.group(0)
"('C:/Python34/abcd.txt')"
>>> m.group(1)
'C:/Python34/abcd.txt'
>>> m.group(1)

answered Aug 10, 2014 at 3:47

khampson

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Comments

hughdbrown · Accepted Answer · 2014-08-10 03:59:30Z

1

Try this simple regex: ('.*?'). It does a non-greedy search for everything enclosed in quotes.

import re
s = "<_io.TextIOWrapper ('C:/Python34/abcd.txt') mode='w' encoding='cp1252'>"
regex = re.compile(r"('.*?')")
m = regex.search(s)
m.group()

It produces this output:

"'C:/Python34/abcd.txt'"

You can also go with re.VERBOSE regexes and groupdict:

import re
s = "<_io.TextIOWrapper ('C:/Python34/abcd.txt') mode='w' encoding='cp1252'>"
regex = re.compile(r"""
    \(
    (?P<quoted>'.*?')
    \)
""", re.VERBOSE)
m = regex.search(s)
m.groupdict()["quoted"]

edited Aug 10, 2014 at 3:59

answered Aug 10, 2014 at 3:49

hughdbrown

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Comments

SebasSBM · Accepted Answer · 2014-08-10 04:20:46Z

1

this regexp will do it:

m = re.search(r"(?<=\()[^\)]*", s)

answered Aug 10, 2014 at 4:20

SebasSBM

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