Simple question I think.. but I couldnt find it with google..
I have a file test.txt.. it contains;
blah
blah2
blah3
What I want to do is;
cat test.txt and then execute;
./script blah
./script blah2
./script blah3
But I want to do it in one line.. What would be the best ways to do it.. ? I know using && is a option.. but maybe there are better ways to pass the string?
No need for cat (or any other external tool for that matter). Something like:
while read line; do ./script "$line"; done < test.txt
does what you want, using the shell builtin read.
As pointed out in the comments, this assumes that you are in the same directory as the script. If not, replace ./script with path/to/script.
./script to a full path. in case the script was in a different dir. but perhaps OP could guarantee that won't happen.
Using xargs:
xargs -n 1 ./script < test.txt
-n option to xargs is good to be reminded about, but the while read line technique is probably more generic.