undefined offset issue in if condition in php

Question

<?php
$get_user="SELECT privillage FROM admin_user WHERE id='".$_SESSION['user_id']."'";
 // echo $get_user;
 $exe_query=mysql_query($get_user);
$row=mysql_fetch_array($exe_query);
 $privillage_data = unserialize($row['privillage']); 
                  //print_r($privillage_data);
                  //$privillage_data1=explode(",",$privillage_data);
 echo '<pre>';
print_r($privillage_data);
$count=count($privillage_data);
 //echo "Count".$count;

 if($privillage_data[0] == '1' || $privillage_data[1] == '1' || $privillage_data[2] == '1' && $count >=1)
    {
        $priv_add ="true";
        echo "add--".$priv_add."</br>";
    }
else{$priv_add ="false";}

if($count >=2 && $privillage_data[1] == '2' || $privillage_data[0] == '2' || $privillage_data[2] == '2')
    {
        $priv_edit ="true";
        echo "edit--".$priv_edit."</br>";
    }
    else{$priv_edit ="false";}

    if($count ==3 && $privillage_data[2] == '3' || $privillage_data[0] == '3' || $privillage_data[1] == '3')
     {
        $priv_delete ="true";
        echo "delete--".$priv_delete."</br>";
    }
    else{$priv_delete ="false";}

?>

i'm getting undefined offset error in if condition,when using the above code!! how to solve the offset issue!! Need in help!!kindly make me simple

where is the definition of your $privillage_data and $count ? — Raphael Müller
– Raphael Müller, Commented Aug 12, 2014 at 6:13
i tried isset()....i undefined issue went,but my expected result will not come — PHP Learner
– PHP Learner, Commented Aug 12, 2014 at 6:19

Rakesh Sharma · Accepted Answer · 2014-08-12 06:19:11Z

3

Looks like you have empty values for array index

try with isset() or empty() like

isset($privillage_data[0]) or !empty($privillage_data[0])

and so on... for all index

so your condition will be

if((!empty($privillage_data[0]) && $privillage_data[0] == '1') || (!empty($privillage_data[1]) && $privillage_data[1] == '1') || (!empty($privillage_data[2]) && $privillage_data[2] == '1') && $count >=1)

and so on for all conditions you are using

answered Aug 12, 2014 at 6:19

Rakesh Sharma

13.7k5 gold badges41 silver badges44 bronze badges

Sign up to request clarification or add additional context in comments.

3 Comments

PHP Learner Over a year ago

if i add isset() means, i can overcome the error,but my privileges are not set for the corresponding user.

Rakesh Sharma Over a year ago

then you need to proper check your array values

Rachael Over a year ago

@kiruthiga, what happens to $priv_add after it is set to true? Do you do something with that variable after all of the if statements?

Rachael · Accepted Answer · 2014-08-12 06:14:35Z

1

Dump out the contents of privillage_data. There's an array key missing that you're expecting. Also, which line above is giving the error?

answered Aug 12, 2014 at 6:14

Rachael

4242 silver badges7 bronze badges

7 Comments

PHP Learner Over a year ago

what do you mean by array key?

Rachael Over a year ago

For example, $privillage_data[1]. That is expecting an array such as this array( 'a', 'b' ) with 'a' being at position 0 and 'b' being at position 1.

PHP Learner Over a year ago

even though, i tried with "$privillage_data ==1" without or condition,the already set privileges are not working correctly

Rachael Over a year ago

What does the "print_r($privillage_data);" display?

PHP Learner Over a year ago

Array ( [0] => 1 )

|

Collectives™ on Stack Overflow

undefined offset issue in if condition in php

2 Answers 2

3 Comments

7 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

3 Comments

7 Comments

Your Answer

Sign up or log in

Post as a guest

Related