If each one of array contains one string push to another array in PHP

Question

I have a very basic question about PHP, I could not solve it with other answers in stackoverflow.

I have an array like :

[0] => this one i need 1
[1] => this one i need 2
[2] => not need this one

so, I want to check for every one, if it contains 'this one i need', then put that into another array

So we must have this array at least :

[0] => this one i need 1
[1] => this one i need 2

I tried to do it like this but it returned Empty array :

foreach($one as $value) {
   if(in_array("my name",$value)) $ok[] = $value;
}

Just to clarify you want to loop through all elements of the array, and if an element = 'XYZ' add to another array? — developer__c
– developer__c, Commented Aug 20, 2014 at 10:40
@buzzlightyear yeah, IF contains one string add to another array. Not equal to ! — Pafo
– Pafo, Commented Aug 20, 2014 at 10:42
Based on your code, $value should be array since you are using it as an array parameter in in_array() function, but based on foreach(), it should not be an array. So which is it? — CrazySabbath
– CrazySabbath, Commented Aug 20, 2014 at 10:47

Satish Sharma · Accepted Answer · 2014-08-20 10:42:31Z

2

try this

<?php

$one = array();

$one[0] = "this one i need 1";
$one[1] = "this one i need 2";
$one[2] = "not need this one";

$ok = array();
$find_str = "this one i need";
foreach($one as $value) {
       if(strpos($value, $find_str) !==false) 
       {
         $ok[] = $value;
       }  
    }


    print_r($ok);
?>

OUTPUT :

Array
(
    [0] => this one i need 1
    [1] => this one i need 2
)

Demo

UPDATE 2 :

as OP's $value is an array

$ok = array();
$find_str = "this one i need";
foreach($one as $value) {
   foreach($value as $val){
       if(strpos($val, $find_str) !==false) 
       {
         $ok[] = $value;
       }  
    }
 }   

    print_r($ok);

answered Aug 20, 2014 at 10:42

Satish Sharma

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6 Comments

Pafo Over a year ago

Error : Warning: strpos() expects parameter 1 to be string, array given in

Satish Sharma Over a year ago

is $value is your array? please put your input array here

Satish Sharma Over a year ago

@Pafo try update 2 if $value is your array and this have values shown in question.

Pafo Over a year ago

Tnx, i tried update two, i have very very big list, every array contains all of values :D

Pafo Over a year ago

I am trying with all answers but i still giving that error !

|

Mark Baker · Accepted Answer · 2014-08-20 10:49:23Z

1

The built-in array_filter() function is intended precisely for this purpose

$needle = 'XYZ';
$newArray = array_filter(
    $originalArray,
    function ($value) use ($needle) {
        return (strpos($value, $needle) !== false);
    }
);

answered Aug 20, 2014 at 10:49

Mark Baker

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Comments

Clément Malet · Accepted Answer · 2014-08-20 10:49:45Z

1

array_filter is the perfect tool to delete unwanted elements based on values

$one[0] = "this one i need 1";
$one[1] = "this one i need 2";
$one[2] = "not need this one";

$wanted_string = 'this one i need';

$array_out = array_filter($one, function($var) use($wanted_string) {
            return strpos($var, $wanted_string) !== false;
});

// array(2) { [0]=> string(17) "this one i need 1" [1]=> string(17) "this one i need 2" }

answered Aug 20, 2014 at 10:49

Clément Malet

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