You can do it like this:
select
substring_index(substring_index(str,',',1),',',-1)AS c1
, CASE WHEN LENGTH(str)-LENGTH(REPLACE(str,',','')) >= 1 THEN substring_index(substring_index(str,',',2),',',-1) ELSE NULL END AS c2
, CASE WHEN LENGTH(str)-LENGTH(REPLACE(str,',','')) >= 2 THEN substring_index(substring_index(str,',',3),',',-1) ELSE NULL END AS c3
, CASE WHEN LENGTH(str)-LENGTH(REPLACE(str,',','')) >= 3 THEN substring_index(substring_index(str,',',4),',',-1) ELSE NULL END AS c4
, CASE WHEN LENGTH(str)-LENGTH(REPLACE(str,',','')) >= 4 THEN substring_index(substring_index(str,',',5),',',-1) ELSE NULL END AS c5
, CASE WHEN LENGTH(str)-LENGTH(REPLACE(str,',','')) >= 5 THEN substring_index(substring_index(str,',',6),',',-1) ELSE NULL END AS c6
, CASE WHEN LENGTH(str)-LENGTH(REPLACE(str,',','')) >= 6 THEN substring_index(substring_index(str,',',7),',',-1) ELSE NULL END AS c7
, CASE WHEN LENGTH(str)-LENGTH(REPLACE(str,',','')) >= 7 THEN substring_index(substring_index(str,',',8),',',-1) ELSE NULL END AS c8
, CASE WHEN LENGTH(str)-LENGTH(REPLACE(str,',','')) >= 8 THEN substring_index(substring_index(str,',',9),',',-1) ELSE NULL END AS c9
, CASE WHEN LENGTH(str)-LENGTH(REPLACE(str,',','')) >= 9 THEN substring_index(substring_index(str,',',10),',',-1) ELSE NULL END AS c10
from test
Demo.
The expressions have two common parts:
LENGTH(str)-LENGTH(REPLACE(str,',','')) >= K - this subexpression determines if the string has at least K delimiters
substring_index(substring_index(str,',',K),',',-1) - this subexpression cuts out the element after the K-th delimiter