If and elif in Python for good programming practices

Question

Hello there I'm currently trying to get a good grasp of the if, elif, else structure in Python. I'm trying some weird combinations in python having a test program to know the output in this if, if, elif, elif, else code. However I'm getting weird results such as this

input = raw_input('Please enter the required digit: ')
intput = int(input)

if intput == 0:
    print 'if1'

if intput == 1:
    print 'if2'
elif intput == 0:
    print 'elif1'
elif intput == 1:
    print 'elif2'
else:
    print 'else'

if I in put 1 it will print "if2", I thought that it will also print "elif2" and other shenanigans when I try to change the "intput == n" code. So my question is do I have to stick to the if,elif, elif, .... n * elifs, else method which seems to me working alright than working with the wacky if,if.... n * ifs, elif, elif, ...n* elifs, else.

Thanks

elif's are only evaluated if the preceding if/elif statement is False, if you had all if statements then they would all be evaluated, if none are True then the else statement will be executed. — Padraic Cunningham
– Padraic Cunningham, Commented Aug 25, 2014 at 12:08

ComputerFellow · Accepted Answer · 2014-08-25 12:07:42Z

8

The elif tree is designed such that at anywhere along if one of the statement turns out to be True, the rest of the elifs will not be evaluated.

Here's a tutorial that might help you understand if else better.

answered Aug 25, 2014 at 12:07

ComputerFellow

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Comments

hackrole · Accepted Answer · 2014-08-25 12:47:59Z

0

this may be more clear to understand:

if input == 0:
    print "if1"

switch(input):
    case 1:
        print "if2"
        break
    case 0:
        print "elif1"
        break
    case 1:
        print "elif2"
        break
    default:
        print "else"
        break

of course, the code does not work.

answered Aug 25, 2014 at 12:47

hackrole

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