I have an object with duplicate values and I want to count all those which have the same value and remove them.
var myArray = [{nr: 'bbc',}, {nr: 'bbc'}, {nr: 'bbc'}, {nr: ccc}];
from this array I want to create another array but remove the duplicated values and count them to be like this.
var myArray = [{nr: 'bbc',amount: 3}}, {nr: ccc,amount: 1}];
You could probably use a better format
var count = {};
for(var i = 0; i < myArray.length; ++i) {
if(typeof count[myArray[i].nr] == 'undefined') {
count[myArray[i].nr] = 0;
}
++count[myArray[i].nr];
}
and this wound yield somehing like:
count = {
bcc: 3,
ccc: 1
};
if you still need it with the structure you specified, then:
var newArray = [];
for(var k in count) {
newArray.push({
nr: k,
amount: count[k]
});
}
If you want the same structure, this will work for you
var newArray = [];
for (var i = 0; i < myArray.length; i++) {
var matched = false;
for (var j = 0; j < newArray.length; j++) {
if(myArray[i].nr === newArray[j].nr){
matched = true;
newArray[j].amount++;
break;
}
};
if(!matched)
newArray.push({nr:myArray[i].nr,amount:1});
};
console.log(newArray);
