Porting new.module() to Python3

Question

How would I implement this in Python3:

def import_code(code, name, add_to_sys_modules=False):
    module = new.module(name)
    sys.modules[name] = module
    do_bookkeeping(module)
    exec(code in module.__dict__)

    return module

Seems like neither __import__ nor importlib actually return the module that can be used for bookkeeping.

Martijn Pieters · Accepted Answer · 2014-09-01 09:39:32Z

4

The new module has been removed from Python 3. You can use types.ModuleType instead, in both Python 2 and 3.

You have your exec() call wrong; it should be:

exec(code, module.__dict__)

You are trying to execute the False result from the code in module.__dict__ expression instead. Using exec() as a function also works in Python 2, so the following works across the major versions:

import types

def import_code(code, name, add_to_sys_modules=False):
    module = types.ModuleType(name)
    if add_to_sys_modules:
        sys.modules[name] = module
    do_bookkeeping(module)
    exec(code, module.__dict__)
    return module

answered Sep 1, 2014 at 9:39

Martijn Pieters

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1 Comment

Kimvais Over a year ago

That's just error made in typing the question in, the actual question is the new module being gone and no way to do new.module(name). Will revise my question

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