php - how to get current dir of server but not current filename?

Question

SOLUTION

$path = $_SERVER['SERVER_NAME'] . $_SERVER['REQUEST_URI'];
$feedtitle = str_replace(" ", "", $feedtitle);
$feedtitle = strtolower($feedtitle);
$path = substr($path, 0, strrpos($path, "/"));
$feedlink = "http://" . "$path" . "/"  . "$feedtitle" . '.xml';

PROBLEM

I am trying to generate a name for an rss feed from another field (feed title). In my query I have :

$path = $_SERVER['SERVER_NAME'] . $_SERVER['REQUEST_URI'];
$feedtitle = str_replace(" ", "", $feedtitle);
$feedtitle = strtolower($feedtitle);
$feedlink = "$path" . "$feedtitle" . '.xml';

If feedtitle is my rss feed, $feedlink will have the value myrssfeed.xml so that part of the code works but I'm having problems with the path. Instead of writing the current path the above writes the current path & the name of the current file! e.g. if the script I'm using for this is named feedlink.php the path that is stored in the $feedlink variable is :

mywebsite.com/mydir/feedlink.phpmyrssfeed.xml

How do I remove the name of the script?

tttony · Accepted Answer · 2014-09-01 20:05:26Z

1

With the str_replace() function

 $feedlink = str_replace("feedlink.php", "",  $feedlink);

answered Sep 1, 2014 at 20:05

tttony

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1 Comment

MBM Over a year ago

Used a combination of your code and Kevin's to resolve it. Thanks.

Kevin Sandow · Accepted Answer · 2014-09-02 15:21:31Z

1

Assuming that you requested the site as mywebsite.com/mydir/feedlink.php you should consider removing everything past the last / and then add your filename to that:

$path = substr($path, 0, strrpos($path, "/") + 1);

edited Sep 2, 2014 at 15:21

answered Sep 1, 2014 at 20:05

Kevin Sandow

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1 Comment

MBM Over a year ago

Using that gives : mywebsite.com/mydirmyrssfeed.xml so it's removing the / after the dir.

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