how to pass file path to a variable using openfiledialog control?

Question

I have this code here which i use in order to upload some stuff in a windows form:

public Form1()
{
    InitializeComponent();
}
private void btnLoad_Click(object sender, EventArgs e)
{
    OpenFileDialog ofd = new OpenFileDialog();
    System.Windows.Forms.DialogResult dr = ofd.ShowDialog();
    if (dr == DialogResult.OK)
    {
        userSelectedFilePath = ofd.FileName;
    }
}

public string userSelectedFilePath
{
    get
    { return tbFilePath.Text;
    }
    set
    {tbFilePath.Text = value;
    }
}

private void btn_compare_Click(object sender, EventArgs e)
{
    string Xml1 = tbFilePath.Text;
    string Xml2 = System.IO.File.ReadAllText(@"C:");
    compare.comparison(Xml1, Xml2);

}

Apparently i'm doing something wrong because i'm not passing the tbFilePath.Text which i need when i have: string Xml1 = tbFilePath.Text;

What is it?

The code in your btn_compare_Click function doesn't make sense. Xml1 contains a path to a file and Xml2 contains the contents of a file, except that file is C:, which is a directory. No way this can work. Are you trying to extract the contents of two different files and compare them? Is that how your comparison() method works? — siride
– siride, Commented Sep 4, 2014 at 13:24
Also, you can help yourself by either using the debugging, or putting Console.WriteLine() statements after assigning variables to see what they contain. You might find that they contain the right thing. — siride
– siride, Commented Sep 4, 2014 at 13:24
Oh, i didn't know that, i'm just trying to pass the path of the file i select — MAL
– MAL, Commented Sep 4, 2014 at 13:25
You code seems to be correct, but have you really selected file in your dialog? :) It happens sometimes — Eldar Dordzhiev
– Eldar Dordzhiev, Commented Sep 4, 2014 at 13:25
@MAL: then what's going on with the ReadAllText(@"C:")? That line doesn't make sense. — siride
– siride, Commented Sep 4, 2014 at 13:26

George Vovos · Accepted Answer · 2014-09-04 13:52:57Z

What you probably want is to compare the contents of 2 files.
As siride said your code does not make sense(see his comment)
Add this method to your class

private string FindFile()
{
   OpenFileDialog ofd = new OpenFileDialog();
   string _xmlPath1 = Environment.GetFolderPath(Environment.SpecialFolder.MyPictures);
   System.Windows.Forms.DialogResult dr = ofd.ShowDialog();
   if (dr == DialogResult.OK)
       return  ofd.FileName;
   else
      return null;

}

And then you can do this:

private void btn_compare_Click(object sender, EventArgs e)
{
    string x1 = System.IO.File.ReadAllText(FindFile(), Encoding.UTF8);
    string x2 = System.IO.File.ReadAllText(FindFile(), Encoding.UTF8);
    //Or if you already have the second file
    //string x2 = System.IO.File.ReadAllText(@"C:\YourPath\someFileName.xml", Encoding.UTF8);
    compare.comparison(x1, x2);
}

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