Split to ArrayList using pattern matcher in Java

Question

String s = "A..?-B^&';(,,,)G56.6C,,,M4788C..,,A1''";
String[] result = s.split("(?=[ABC])");
System.out.println(Arrays.toString(result));

Output:

 [A..?-, B^&';(,,,)G56.6, C,,,M4788, C..,,, A1'']

Please refer to the The split in the above case. I am trying to separate strings based on A, B orC. How can I get the the same split strings into an ArrayList using pattern matcher? I could not figure out how to group in the below code.

Pattern p = Pattern.compile("(?=[ABC])");
Matcher m = p.matcher(s);
List<String> matches = new ArrayList<>();
while (m.find()) {
   matches.add(m.group());
}

Also suppose I have few characters before first occurance of A, B or C and I want to combine with first element in ArrayList. ,,A..

Appreciate the help.

Can't you use String[] result = Pattern.compile("(?=[ABC])").split(s, 0); ? — Florent Bayle
– Florent Bayle, Commented Sep 12, 2014 at 12:47

Deltharis · Accepted Answer · 2014-09-12 13:23:25Z

4

[ABC][^ABC]*

If I didn't ommit any edge case that should work with the code you provided

For the extra question, you could possibly add (^[^ABC]*)* to the beggining, but that makes it slower and look less readable, not to mention it will only work for single-line strings to check. I would recommend just parsing the beggining characters manually, treating it like a special case it is.

edited Sep 12, 2014 at 13:23

answered Sep 12, 2014 at 12:49

Deltharis

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1 Comment

Mena Over a year ago

Your answer's much better than mine. +1 and deleting.

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