Typedefs for function pointer type

Question

I got a typedef function pointer type defined as

typedef double(*fun)(const eValue&);

why is this line throwing an error: missing type specifier -int assumed? and syntax error: missing , before '&'?

can anyone help me?

Thanks in advance.

AlexD · Accepted Answer · 2014-09-13 00:08:11Z

1

The reason likely is that eValue is undefined.

Assuming it is an enum (just guessing from its name) try

enum eValue;
typedef double(*fun)(const eValue&);

answered Sep 13, 2014 at 0:08

AlexD

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