Is there any possibility to break a loop while calling a function?

Question

Let's say I have a simple code:

while(1) {
  myend();
}

function myend() {
  echo rand(0,10);
  echo "<br>";
  if(rand(0,10) < 3) break;
}

This will not work with error code 'Fatal error: Cannot break/continue 1 level on line'.

So is there any possibility to terminate the loop during a subfunctin execution?

No, you must instead return a value from the function and break based on its value — Steve
– Steve, Commented Sep 15, 2014 at 12:58

nickb · Accepted Answer · 2014-09-15 12:58:55Z

3

Make the loop condition depend upon the return value of the function:

$continue = true;
while( $continue) {
    $continue = myend();
}

Then, change your function to be something like:

function myend() {
  echo rand(0,10);
  echo "<br>";
  return (rand(0,10) < 3) ? false : true;
}

answered Sep 15, 2014 at 12:58

nickb

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2 Comments

georg Over a year ago

rather, do {... } while(fun()).

hsz Over a year ago

myend in my case will be evaluated too.

Simon Brahan · Accepted Answer · 2014-09-15 13:00:55Z

1

There isn't. Not should there be; if your function is called somewhere where you're not in a loop, your code will stop dead. In the example above, your calling code should check the return of the function and then decide whether to stop looping itself. For example:

while(1) {
  if (myend())
    break;
}

function myend() {
  echo rand(0,10);
  echo "<br>";
  return rand(0,10) < 3;
}

answered Sep 15, 2014 at 13:00

Simon Brahan

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Comments

Kingalione · Accepted Answer · 2014-09-15 13:01:25Z

1

Use:

$cond = true;
while($cond) {
  $cond = myend();
}

function myend() {
  echo rand(0,10);
  echo "<br>";
  if(rand(0,10) < 3) return false;
}

answered Sep 15, 2014 at 13:01

Kingalione

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