Deserialize XML with optional tags

Question

I have an XML with an optional tag as follows:

<Config>
    <CheckForCompleteTransform>true</CheckForCompleteTransform>
    <!-- more tags -->
</Config>

And the class-definition:

public class config {
    [System.Xml.Serialization.XmlElement("CheckForCompleteTransform")]
    public bool? CheckForCompleteTransform { get; set; }
}

This works if I either set the tag to what I provided within my example-XML above or I omit it completely. But what if I provide the tag as <MyTag/>? If this notation is used I want the serializer to set the corresponding property within my class to true, but I awlays get a

System.FormatException: the string literal '' is not valid for type Boolean

Any ideas on how to achieve this?

Community · Accepted Answer · 2017-05-23 12:05:49Z

2

Check this here

u can use [XmlElement("CheckForCompleteTransform", IsNullable=true)] CheckForCompleteTransform property in your class

public class config
    {
        [XmlElement("CheckForCompleteTransform", IsNullable = true)]
        public bool? CheckForCompleteTransform { get; set; }
    }

and add xsi:nil="true" attribute to CheckForCompleteTransform tag like this

<CheckForCompleteTransform xsi:nil="true" />

edited May 23, 2017 at 12:05

CommunityBot

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answered Sep 16, 2014 at 11:30

Akanksha Gaur

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1 Comment

MakePeaceGreatAgain Over a year ago

This works, although I cannot change the actual XML (only for development-purposes I have control on it:( the actual XML is generated by 3rd party and therefor not modifyable)

FishySwede · Accepted Answer · 2014-09-16 11:32:56Z

2

I haven't verified this myself, but have you tried adding a

[XmlElement(IsNullable = true)]

attribute to the CheckForCompleteTransform ?

EDIT:

Ok, how about together with

DefaultValueAttribute(true);

edited Sep 16, 2014 at 11:32

answered Sep 16, 2014 at 11:23

FishySwede

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1 Comment

MakePeaceGreatAgain Over a year ago

Still the same exception: "string literal '' is no valid value for type Boolean"

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