Printing data from a loop in multiple place without running the loop again

Question

Lets I have an array like this

$age=array("Peter"=>"35","Ben"=>"37","Joe"=>"43");

<?php 
 $age=array("Peter"=>"35","Ben"=>"37","Joe"=>"43");
?>
    <div id="3">
          <!-----result of foreach loop---->
    </div>
    <div id="1">
         <?php 
            foreach ($age as $key => $value) {?>
                    <p><?php echo $value;?></p>
            <?php
            }
         ?>
    </div>
    <div id="2">
        <!-----result of foreach loop---->
    </div>
<?php
?>

I want to print the same result in <div id="2"> and in <div id="3"> , without loop through the array in , I just want to use the loop only for one time .

Why? What are you trying to achieve by not having multiple loops? You could concatenate your loop into a variable and echo it in multiple places. — Scuzzy
– Scuzzy, Commented Sep 25, 2014 at 5:07
If I have an array of million items , then surely my script will be slow . — Mithun Sarker
– Mithun Sarker, Commented Sep 25, 2014 at 5:09

Philip G · Accepted Answer · 2014-09-25 05:11:10Z

3

 <?php 
            $pAge = "";
            foreach ($age as $key => $value) {
               $pAge .= "<p>" . $value . "</p>";
            }
 ?>

    <div id="3">
          <?= $pAge; ?>
    </div>
    <div id="1">
          <?= $pAge; ?>
    </div>

answered Sep 25, 2014 at 5:11

Philip G

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Comments

Kamehameha · Accepted Answer · 2014-09-25 05:11:04Z

2

You can try putting all of them in a variable and then echo them out.
Something like this -

<?php 
 $age=array("Peter"=>"35","Ben"=>"37","Joe"=>"43");
 $display_str = "";
 foreach ($age as $key => $value) {
    $display_str .= $value;
 }
?>
<div id="1">
  <?php echo $display_str;?>     
</div>
<div id="2">
    <!-----result of foreach loop---->
    <?php echo $display_str;?>
</div>

answered Sep 25, 2014 at 5:11

Kamehameha

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Comments

S.Pols · Accepted Answer · 2014-09-25 05:11:25Z

2

Just store the html before the div part and print it three times:

<?php 
    $age=array("Peter"=>"35","Ben"=>"37","Joe"=>"43");

    $htmlString = '';
    foreach ($age as $key => $value) 
    {
        $htmlString .= '<p>'.$value.'</p>';
    }
?>

<div id="3">
   <?=$htmlString?>
</div>
<div id="1">
   <?=$htmlString?>
</div>
<div id="2">
   <?=$htmlString?>
</div>

answered Sep 25, 2014 at 5:11

S.Pols

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Comments

Vimalnath · Accepted Answer · 2014-09-25 05:13:31Z

Just store the result values in array in use in anywhere like this:

<?php 
$age=array("Peter"=>"35","Ben"=>"37","Joe"=>"43");
?>
    <div id="3">
          <!-----result of foreach loop---->
    </div>
    <div id="1">
         <?php 
            $res = array();
            foreach ($age as $key => $value) {?>
                    <p><?php 
                    $res[] = $value;
                    echo $value;?></p>
            <?php
            }
         ?>
    </div>
    <div id="2">
        <!-----result of foreach loop---->
        <?php
            echo '<pre>';
            print_r($res); ?>
        <p><?php 
            echo $res[0];
            echo $res[1];
            echo $res[2];
        ?></p>
    </div>
<?php
?>

Dinesh · Accepted Answer · 2014-09-25 05:27:11Z

1

You can do this like as:

<div id="1">


 <?php 
        $html="";
        foreach ($age as $key => $value) {


                $html .= "<p>".$value."</p>";
                }
               echo $html;
                ?>

</div>
<div id="2">
    <?php echo $html; ?>
</div>

edited Sep 25, 2014 at 5:27

answered Sep 25, 2014 at 5:12

Dinesh

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1 Comment

Philip G Over a year ago

Why are you echoing $html in the loop?

Hardik Solanki · Accepted Answer · 2014-09-25 05:33:13Z

1

You can also do it using :

<?php 
  function myfunction($value,$key)
  {
      echo "$value<br>";
  }

 $age=array("Peter"=>"35","Ben"=>"37","Joe"=>"43");
?>
    <div id="3">
         <?php array_walk($age,"myfunction"); ?>
    </div>
    <div id="1">
        <?php array_walk($age,"myfunction"); ?>
    </div>
    <div id="2">
        <?php array_walk($age,"myfunction"); ?>
    </div>

answered Sep 25, 2014 at 5:33

Hardik Solanki

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