PHP - Get the key of a subarray based on a value within

Question

I'm trying to get the key of a subarray based on a value in that subarray. So, based on the example below, how can I return the key of the array containing 'apple'?

Array ( 
    [0] => Array ( 
        [fruit] => apple 
        [colour] => green 
    ) 
    [1] => Array ( 
        [fruit] => banana 
        [colour] => yellow 
    ) 
)

So logically, something like:

if ('apple' is in $subarray) {
    echo $subarray_key;
}

Thanks in advance.

You have to use a loop to check all the values.

Marty
– Marty

2014-09-26 01:03:36 +00:00
Commented Sep 26, 2014 at 1:03 — Marty
– Marty, Commented Sep 26, 2014 at 1:03

webNeat · Accepted Answer · 2014-09-26 01:05:53Z

4

Assuming that your array is stored in $arr variable, you can do

foreach($arr as $key => $value){
    if(in_array('apple',$value){
        echo $key;
    }
}

answered Sep 26, 2014 at 1:05

webNeat

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1 Comment

flowfab Over a year ago

a closing bracket (for the if) is missing.. foreach($arr as $key => $value){ if(in_array('apple',$value) ) { echo $key; } }

DaOgre · Accepted Answer · 2014-09-26 01:04:28Z

2

 foreach($array as $key => $val){
      if($val == 'apple'){
           print $key;
      }
 }

You can use array keys and do some other stuff but for the most part you're going to end up just iterating through the array anyways

answered Sep 26, 2014 at 1:04

DaOgre

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1 Comment

webNeat Over a year ago

I guess $val will be an array which contains the value 'apple' not the value itself

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