PHP class as argument

Question

Is it possible to do this?

class Foo
{
    public function __construct($bar)
    {
        $barish = new $bar();
        $barish->woo();
    }
}

class Bar
{
    function woo()
    {
        echo "wooooo";
        die();
    }
}

// Here the magic should happen
$foo = new Foo(Bar);

I expect wooooo but I get "Use of undefined constant Bar".

Legionar · Accepted Answer · 2014-10-07 14:24:18Z

2

You are missing '':

class Foo
{
    public function __construct($bar)
    {
        $barish = new $bar();
        $barish->woo();
    }
}

class Bar
{
    function woo()
    {
        echo "wooooo";
        die();
    }
}

// Here the magic should happen
$foo = new Foo('Bar');

answered Oct 7, 2014 at 14:24

Legionar

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1 Comment

Matteo B. Over a year ago

This is the right solution at the moment. But it is damn ugly to pass a classes name as string to a function... not only for type hinting and refactoring reasons. I want something like the Type from C# please :D . The Type-solution is just so smooth and opens up sooo many possibilities.

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