Check if String contains regex match

Question

What i want is to check if there is a number followed by spaces and another number, without any "," in between, anywhere in the String

Currently i am doing this:

Pattern pattern = Pattern.compile("[0-9][\" \"]+[0-9]");
Matcher matcher = pattern.matcher(input);
if(matcher.find()) return false;

and it works just fine. But i was wondering if there is any other simpler way of achieving this?

musical_coder · Accepted Answer · 2014-10-09 00:32:15Z

1

Since it's an assignment, I won't write out the code, but an alternative solution is:

Split the string on the , token (using String.split())
For each member of the resulting split array:
- Trim the leading and trailing spaces from the member
- If the trimmed member is an integer (I'll let you figure out how to determine that):
  - It doesn't meet the criteria you specified
- Else:
  - It's possible that the token could meet your criteria (of containing multiple integers and spaces but no commas. There are several ways you could determine this: do a split on " "; use a while loop, or maybe something else. I'll let you figure that out.

edited Oct 9, 2014 at 0:32

answered Oct 9, 2014 at 0:15

musical_coder

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2 Comments

musical_coder Over a year ago

No, in that case, split[0] would be 1 2 (the space would be preserved), which of course isn't an integer.

musical_coder Over a year ago

Ah, I think I was trying to just check if each token is an integer, but you're looking for the case where two or more integers are not properly separated. I updated my answer, that should be more than enough to get you started.

Villat · Accepted Answer · 2019-07-17 23:48:51Z

0

Your solution is good enough, you could try by the positive way like

Pattern pattern = Pattern.compile("^[1-9](,[1-9])*$");
Matcher matcher = pattern.matcher(input);
if(matcher.matches()) return true;

answered Jul 17, 2019 at 23:48

Villat

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