Java getResource() unexpected path

Question

I wanted the url of a resource in the following form

C:/Users/.../build/classes/jam/lena1.png

To achieve this I wrote the following code

System.out.println(getClass().getResource("lena1.png").getPath());

but it returns

/C:/Users/.../build/classes/jam/lena1.png

Why is the extra forward slash appearing before the url?

if System.out.println(getClass().getResource("lena1.png").toString()); is written then output is : file:/C:/Users/.../build/classes/jam/lena1.png — KiKMak
– KiKMak, Commented Oct 11, 2014 at 10:32
I'm getting the resource, but the method getPath() returns the URL with an additional forward slash — KiKMak
– KiKMak, Commented Oct 11, 2014 at 10:41

Little Santi · Accepted Answer · 2014-10-11 09:47:23Z

5

Regard that Class.getResource() returns a URL, and URLs are not only file paths: A URL involves a protocol, a host, a port, and a path. And it has its own notation and format.

What you are getting in your example is the path part of the URL, and the path always starts by a slash, according to RFC2396.

If you want to get a File from a URL, you could use new File(url.toURI())... assumming that the input URL is actually referencing a local file path.

answered Oct 11, 2014 at 9:47

Little Santi

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6 Comments

KiKMak Over a year ago

Thanks for your suggestion, but url.toURI() doesn't work, it gives the same result.

Little Santi Over a year ago

I insist: First, get a URI from the URL with url.toURI(), then create a File object passing the URI as a parameter. Then, if you want the absolute local path, you can get it with file.getAbsolutePath().

KiKMak Over a year ago

but there is a little problem, tthis method returns path with back slash

Little Santi Over a year ago

If you're running your program on a Windows plattform, the correct path separator is the back slash. Is it a problem for you? Realise that the value returned by file.getAbsolutePath() is a valid path.

KiKMak Over a year ago

Yes, its a valid path but in java if the path has backslash it should be something like "C:\\Users\\..." but instead it is like "C:\Users\..."

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user207421 · Accepted Answer · 2014-10-11 09:48:06Z

1

Because it's a URL, not a filename.

The question itself is odd. What do you care what the path of the URL is?

edited Oct 11, 2014 at 9:48

answered Oct 11, 2014 at 9:41

user207421

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1 Comment

KiKMak Over a year ago

I need the path for using it in an external library.

iColdBeZero · Accepted Answer · 2014-10-11 09:36:20Z

-1

Leading slash to denote the root of the classpath. Try this : System.out.println(getClass().getResource("/lena1.png").getPath());

answered Oct 11, 2014 at 9:36

iColdBeZero

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1 Comment

user207421 Over a year ago

The root of the CLASSPATH isn't C:/, and your suggested code isn't correct either: it should be "/jam/lena1.png".

govindpatel · Accepted Answer · 2014-10-11 09:37:03Z

-1

use this

String s = (getClass().getResource("lena1.png").getPath()).substring(1);
System.out.println(s);

answered Oct 11, 2014 at 9:37

govindpatel

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1 Comment

Tom Over a year ago

This will remove the slash, but doesn't not clarify why it is there.

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