Creating regular expression in php

Question

My attempt

preg_match("/^logs.\d{24}.\d{24}.{4}$/", $input_line, $output_array);
If matched return \d{24} in echo

String

logs/532523532543353444444444/532523532543353444444444.log

Preg match peseudo-code : logs/{24 digitals}/{same24digits}.log

Both \d{24} are the same number

Question How to get the : If matched return \d{24} in echo

Community · Accepted Answer · 2020-06-20 09:12:55Z

2

You can use:

if (preg_match('~^logs/(\d{24})/\1\.log$~', $input_line, $m))
   echo $m[1];

\1 ia back-reference to first captured group i.e. (\d{24})

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answered Oct 15, 2014 at 19:49

anubhava

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1 Comment

Ok so the $m[1] result is 893259838902389058903258/893259838902389058903258.log I just need the number 893259838902389058903258

nu11p01n73R · Accepted Answer · 2014-10-15 19:50:57Z

2

logs\/(\d{24})\/\1.log

answered Oct 15, 2014 at 19:50

nu11p01n73R

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