I have a bash script as below, and I want it to read two dates as parameters, for example: myshell date1 date2. How do I assign parameters to variables date1 and date2?
sed "s/$date1/$date2/g" wlacd_stat.xml >tmp.xml
mv tmp.xml wlacd_stat.xml
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4 Answers
You use $1, $2 in your script. E.g:
date1="$1"
date2="$2"
sed "s/$date1/$date2/g" wlacd_stat.xml >temp.xml
mv temp.xml wlacd_stat.xml
Comments
To iterate over the parameters, you can use this shorthand:
#!/bin/bash
for a
do
echo $a
done
This form is the same as for a in "$@".
answered Apr 15, 2010 at 15:11
Dennis Williamson
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Comments
Bash arguments are named after their position.
Moreover, if you need to handle one argument after the other, you can shift them and always use $1:
while [ $# -gt 0 ]
do
echo $1
shift
done
Comments
$0
$1
$2
And so on will contain the script name, then the first and the second line argument.
answered Apr 15, 2010 at 13:30
Simone Margaritelli
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