How can I make an array of type "class" in PHP?

A Member object represents one member. You're trying to overload it to represent or handle many members, which doesn't really make sense. In the end you'll want to end up with an array that holds many Member instances, not the other way around:

$members = array();
for (...) {
    $members[] = new Member($name, $family);
}

Most likely you don't really need your Member class to do anything really; the extraction logic should reside outside of the Member class, perhaps in an Extractor class or something similar. From the outside, your code should likely look like this:

$parser  = new TextFileParser('my_file.txt');
$members = $parser->extractMembers();

I think you should have two classes :

• The first one, Fetcher (or call it as you like), with your function.
• The second one, Member, with the properties Name and Family.

It is not the job of a Member to fetch in your text, that's why I would make another class.

In your function, do your job, and in the loop, do this :

for($i = 0; $i < 10; ++$i){
    $member = new Member();
    $member->setName($name);
    $member->setFamily($family);
    // The following is an example, do what you want with the generated Member
    $this->members[$i] = $member;
}

The problem here is that you are not using the object of type Member as array correctly. The correct format of your code would be:

class Member{
    public $Name;
    public $Family;

    public function Fetch_Name(){
      for($i=0;$i<10;$i++){
        $this->Name[$i] = 'I find the name using RegExp and return the value to be stored here';
        $this->Family[$i] = 'I find the family using RegExp and return the value to be stored here';
      }
    }
}

First, $this->Name not $this->$Name because Name is already declared as a member variable and $this->Name[$i] is the correct syntax because $this reference to the current object, it cannot be converted to array, as itself. The array must be contained in the member variable.

L.E: I might add that You are not writing your code according to PHP naming standards. This does not affect your functionality, but it is good practice to write your code in the standard way. After all, there is a purpose of having a standard.

Here you have a guide on how to do that.

And I would write your code like this:

class Member{
    public $name;
    public $family;

    public function fetchName(){
      for($i=0;$i<10;$i++){
        $this->name[$i] = 'I find the name using RegExp and return the value to be stored here';
        $this->family[$i] = 'I find the family using RegExp and return the value to be stored here';
      }
    }
}

L.E2: Seeing what you comented above, I will modify my answer like this:

So you are saying that you have an object of which values must be stored into an array, after the call. Well, after is the key word here:

1. Initialize your object var: $member = new Memeber(); $memebr->fechNames();

2. Initialize and array in foreach

   $Member = new Member();
   
   foreach ($Member->Name as $member_name){
       $array['names'][] = $member_name;
   }
   
   foreach ($Member->Family as $member_family) {
       $array['family'][] = $member_family;
   }
   var_dump($array);
   

Is this more of what you wanted?

Hope it helps!
Keep on coding!
Ares.