unable to get html source from url

Question

I have read most of the answers with my question. But I get nothing from this url. Well, actually I'm getting " "

This is the url:

http://www.casadellibro.com/busqueda-generica?busqueda=9783126759120&nivel=5&auto=0&maxresultados=-1

My code:

System.Net.WebRequest req = System.Net.WebRequest.Create(url);
System.Net.WebResponse resp = req.GetResponse();
System.IO.StreamReader sr = new System.IO.StreamReader(resp.GetResponseStream());
string response = sr.ReadToEnd();

Any idea?

Thank you in advance.

Take a look at How to Ask to read how to structure your question and help us to answer you ;) — mithrop
– mithrop, Commented Oct 23, 2014 at 13:21

Community · Accepted Answer · 2017-05-23 11:57:10Z

1

Getting HTML code from a website. You can use code like this.

string urlAddress = "http://google.com";

HttpWebRequest request = (HttpWebRequest)WebRequest.Create(urlAddress);
HttpWebResponse response = (HttpWebResponse)request.GetResponse();
if (response.StatusCode == HttpStatusCode.OK)
{
  Stream receiveStream = response.GetResponseStream();
  StreamReader readStream = null;
  if (response.CharacterSet == null)
    readStream = new StreamReader(receiveStream);
  else
    readStream = new StreamReader(receiveStream, Encoding.GetEncoding(response.CharacterSet));
  string data = readStream.ReadToEnd();
  response.Close();
  readStream.Close();
}

This will give you the returned HTML code from the website. But find text via LINQ is not that easy. Perhaps it is better to use regular expression but that does not play well with HTML code

Read all reactions here: Get HTML code from website in C#

edited May 23, 2017 at 11:57

CommunityBot

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answered Oct 23, 2014 at 13:24

Matheno

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3 Comments

Noarge Over a year ago

Thank you for your quick response. But I'm getting the same result. Data = " "

Matheno Over a year ago

request and response are passed OK? Do you have any errors when debugging?

Noarge Over a year ago

Yes, they passed OK. And no errors. StatusCode = OK, StatusDescription = OK, ContentLength = 4

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