Okay so what I did was
def countvowels(st):
result=st.count("a")+st.count("A")+st.count("e")+st.count("E")+st.count("i")+st.count("I")+st.count("o")+st.count("O")+st.count("u")+st.count("U")
return result
This works(I'm aware indentation might be wrong in this post, but the way I have it indented in python, it works).
Is there a better way to do this? Using for loops?
I would do something like
def countvowels(st):
return len ([c for c in st if c.lower() in 'aeiou'])
sum(c.lower() in 'aeiou' for c in st) saves making a temporary listThere's definitely better ways. Here's one.
def countvowels(s):
s = s.lower()
return sum(s.count(v) for v in "aeiou")
You can do that using list comprehension
def countvowels(w):
vowels= "aAiIeEoOuU"
return len([i for i in list(w) if i in list(vowels)])
list constructors. Strings are iterable in python.You could use regex pattern to do this easily. But it looks to me, that you want to do it without. So here is some code to do so:
string = "This is a test for vowel counting"
print [(i,string.count(i)) for i in list("AaEeIiOoUu")]
you can do it in various ways, first look in google before asking, i had copy pasted 2 of them
def countvowels(string):
num_vowels=0
for char in string:
if char in "aeiouAEIOU":
num_vowels = num_vowels+1
return num_vowels
data = raw_input("Please type a sentence: ")
vowels = "aeiou"
for v in vowels:
print v, data.lower().count(v)
You can also try Counter from collections (only available from Python 2.7+) as shown below . It'll show how many times each letter has been repeated.
from collections import Counter
st = raw_input("Enter the string")
print Counter(st)
But you want vowels specifically then try this.
import re
def count_vowels(string):
vowels = re.findall('[aeiou]', string, re.IGNORECASE)
return len(vowels)
st = input("Enter a string:")
print count_vowels(st)
Here is a version using map:
phrase=list("This is a test for vowel counting")
base="AaEeIiOoUu"
def c(b):
print b+":",phrase.count(b)
map(c,base)