Angularjs return $location url without parameters

Question

My application have a url like this: "http://host:port/mySystem?x.system"

The x.system had to be added because a legacy application need this stuff on all url's, and my application depends on this legacy application.

My problem is that i need the pure url of the system like this : "http://host:port/mySystem", but when i use $location.absUrl() it returns : "http://host:port/mySystem?x.system"

There's a way to get the url with $location (or another service on angular), without the parameters ?

location.host + location.port() + location.path, something like this — uladzimir
– uladzimir, Commented Oct 29, 2014 at 13:57
@BiAiB, using Angular, this is a bad habit to use window.location — wintenbb
– wintenbb, Commented Oct 29, 2014 at 14:01

Terry · Accepted Answer · 2014-10-29 14:28:43Z

2

You can use $location to pull out whatever you need to build a URL. Here is a Plunker from the official docs that shows all the different parts. You probably want something like this:

function buildBaseUrl() {
  return $location.protocol() + '://' + $location.host() + ':' + $location.port() + $location.path()
}

answered Oct 29, 2014 at 14:28

Terry

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