Python check word exist in a string contents in any cases

Question

Is this simple string_line to find keyword exist or not.

Keyword exist but still it's go inside if condition.

Keyword exist but in mixed case why can not capture mixed case lowercase or uppercase.

string_line = '<p>this is real crm and for real CRM amd and Read Crm.</p>\r\n'
keyword = 'Real CRM'

if keyword not in string_line:
    print "Keyword Not Found____"
else:
    print "Keyword Found____"

How to check keyword exist in same case or mixed case then return keyword found in string?

101 · Accepted Answer · 2014-10-30 05:22:42Z

3

Change the cases to be the same:

string_line = '<p>this is real crm and for real CRM amd and Read Crm.</p>\r\n'
keyword = 'Real CRM'

if keyword.lower() in string_line.lower():
    print "Keyword found"
else:
    print "Keyword not found"

answered Oct 30, 2014 at 5:22

101

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2 Comments

Jaykumar Patel Over a year ago

is this return if keyword present in capitalized REAL CRM in a string ?

101 Over a year ago

This is completely case insensitive, so it will always match if the string contains the keyword. The string and keyword can both be any or mixed case. Is that what you wanted?

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