Python Regular expression to extract a substring

Question

I have a string

" request.addParameter('page','/TMRMKUOHY/RPM/Store/srrreVkew.jsp?resODFlag','N','',true,false); ".

I want to extract the part

" '/TMRMKUOHY/RPM/Store/srrreVkew.jsp?resODFlag' "

out of this string. I tried several combinations of regex (using re module in python) but can't find the exact desired pattern that gives me the substring out of the main string.

Can you put those combinations of regex that you tried into your question? — Jerry
– Jerry, Commented Oct 31, 2014 at 6:59
pat = re.search("\'\/[a-z]*[A-Z]*[./+]",string1) pat = re.search("\'\/(.+)\?(.\w)",string1) pat = re.search("\'\/(.+)?(.\w*)",string1) pat = re.search("\'\/(.+)?(.\W*)",string1) pat = re.search("\'\/(.+)?(\w*\d*)\'",string1) pat = re.search("\'\/(.+)?(\w*\d*)\'[^,]",string1) pat = re.search("\'\/(\w+)?'",string1) — harveyD
– harveyD, Commented Oct 31, 2014 at 7:04
@Harvey In the question please, not in comments. You can edit your question and add that at the end. — Jerry
– Jerry, Commented Oct 31, 2014 at 7:04

vks · Accepted Answer · 2014-10-31 07:02:43Z

1

'([^']+)'

You can try this.

Do print re.findall(r"'([^']+)'",x)[1].

Here x is your string.Basically it is extracting the second group.

See demo.

http://regex101.com/r/yG7zB9/2

answered Oct 31, 2014 at 7:02

vks

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1 Comment

harveyD Over a year ago

I didn't. In fact you're a STAR.

nu11p01n73R · Accepted Answer · 2014-10-31 07:08:06Z

0

Use the regex

'\/[^']+'

The code can be written as

x="  request.addParameter('page','/TMRMKUOHY/RPM/Store/srrreVkew.jsp?resODFlag','N','',true,false); ".
re.findall(r"'\/[^']+'", x)"
["'/TMRMKUOHY/RPM/Store/srrreVkew.jsp?resODFlag'"]

see how the regex works http://regex101.com/r/pK9mI8/1

you can also use search function to search and find the substring matching the pattern as

 re.search(r"'\/[^']+'", x).group()
"'/TMRMKUOHY/RPM/Store/srrreVkew.jsp?resODFlag'"

answered Oct 31, 2014 at 7:08

nu11p01n73R

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Comments

Avinash Raj · Accepted Answer · 2014-10-31 07:09:09Z

0

Seems like you want something like this,

>>> import re
>>> s = "  request.addParameter('page','/TMRMKUOHY/RPM/Store/srrreVkew.jsp?resODFlag','N','',true,false); "
>>> re.search(r"'(/[^']*)'", s).group(1)
'/TMRMKUOHY/RPM/Store/srrreVkew.jsp?resODFlag'

answered Oct 31, 2014 at 7:09

Avinash Raj

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Comments

Kasravnd · Accepted Answer · 2014-10-31 07:13:40Z

0

You are not forced to use regex you can use split():

>>> s.split(',')[1]
"'/TMRMKUOHY/RPM/Store/srrreVkew.jsp?resODFlag'"

answered Oct 31, 2014 at 7:13

Kasravnd

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1 Comment

Kasravnd Over a year ago

yep, for extract a substring you can use some ways that regex is one of them , so if you find this answer useful you can tell this to community by up voting ,

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