How to use preg_match correctly inside an array index?

Question

code:

$array[ ( preg_match( '/pdf-\d/', $key ) ? true : false ) + '[' + ( preg_match( '/pdf-total-\d/', $key ) ? true : false ) + ']' ]

output should be:

$array['pdf-1[pdf-total-1]']

You haven't done yourself any favors cramming that all onto one line. — Marty
– Marty, Commented Nov 5, 2014 at 9:22
preg_match( '/pdf-\d/', $key ) will return true or false, you dont need the ? true : false, if you use preg_match( '/pdf-(\d)/', $key ) this will return one array with the (\d) found — nicearma
– nicearma, Commented Nov 5, 2014 at 9:31
Thanks for reply guys, but I figured out it myself. I just appended a hidden input in my jquery with value and match it in my php. Thanks a lot. — heero
– heero, Commented Nov 5, 2014 at 12:06
@nicearma: oh! preg_match returns 0 when there is no match, 1 when a match is found, false when an error occurs. — Casimir et Hippolyte
– Casimir et Hippolyte, Commented Dec 13, 2014 at 23:05
@nicearma: even if you use a capture group preg_match will not return the matched content! — Casimir et Hippolyte
– Casimir et Hippolyte, Commented Dec 13, 2014 at 23:13

dynamic · Accepted Answer · 2014-11-05 09:28:44Z

2

Actually, you are using ternary operator:

preg_match( '/pdf-\d/', $key ) ? true : false

This returns true or false but never pdf-1 nor [pdf-total-1]

Maybe you want more something like this:

$array[ 
        ( preg_match( '/pdf-\d/', $key ) ? $key: false ) . 
        '[' . ( preg_match( '/pdf-total-\d/', $key ) ? $key: false ) . ']' 
      ]

But it doesn't have much sense in any case because $key matches the first pattern or it matches the second

edited Nov 5, 2014 at 9:28

answered Nov 5, 2014 at 9:23

dynamic

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