Copying of structure array to another larger structure array without individual element access?

Question

I want to copy all the element of small structure array to larger structure array without copying individual element from the structure my code is below

This question is asked here copy smaller array into larger array before but i couldn't find appropriate reply.please help me

  struct st 
 {
  int i;
  char ch[10];
 };

 int main()
  {
   struct st var[2]={1,"hello",2"bye"};
   struct st largevar[3];
   strcpy(largevar,var);// this is bad i guss but is there any way to copy without individual element access?
  }

memcpy?

IllusiveBrian
– IllusiveBrian

2014-11-05 16:44:19 +00:00
Commented Nov 5, 2014 at 16:44 — IllusiveBrian
– IllusiveBrian, Commented Nov 5, 2014 at 16:44

Serge Ballesta · Accepted Answer · 2014-11-05 16:41:48Z

1

You were not very far, but the correct function in memcpy : strcpy copies null terminated strings, memcpy copies arbitrary memory blocks :

You could use :

memcpy(largevar, var, sizeof(struc st) * 2);

answered Nov 5, 2014 at 16:41

Serge Ballesta

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Gopi · Accepted Answer · 2014-11-05 16:43:56Z

0

You should be using memcpy() as shown below and not strcpy().

#include<stdio.h>
#include<string.h>  

    struct st 
     {
      int i;
      char ch[10];
     };

     int main()
      {
          int i =0;
       struct st var[2]={{1,"hello"},{2,"bye"}};
       struct st largevar[3];
       memcpy(largevar,var,sizeof(struct st) * 2);
       for(i=0;i<2;i++)
       printf("%d %s\n",largevar[i].i,largevar[i].ch);
       return 0;
      }

answered Nov 5, 2014 at 16:43

Gopi

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