Set the value of a PHP Variable equal to the value of a HTML Element

Question

I'm working on a PHP code that checks the status of a server. The code works perfectly when it's used like this:

<?php
$SERVER_IP = "217.198.136.31";
$SERVER_PORT = "25565";
$QUERY_PORT = "25565";
?>

However, instead of manually assigning the values for the php variables I need to get them from two HTML input elements. I've tried the following code but it doesn't work:

<input id="checkip" name="checkip" value="217.198.136.31">
<input id="checkport" name="checkport" value="25565">

<?php
$SERVER_IP = $_POST['checkip'];
$SERVER_PORT = $_POST['checkport'];
$QUERY_PORT = $_POST['checkport'];
?>

I can't figure out why it isn't working, doesn't the $_POST get the exact value from the HTML elements and put them in the PHP variables? What should I do to get the same result for the last code?

Are you sending a POST request?

Mostafa Talebi
– Mostafa Talebi

2014-11-10 07:23:34 +00:00
Commented Nov 10, 2014 at 7:23 — Mostafa Talebi
– Mostafa Talebi, Commented Nov 10, 2014 at 7:23
wrap inside a form and submit

Arun Killu
– Arun Killu

2014-11-10 07:26:09 +00:00
Commented Nov 10, 2014 at 7:26 — Arun Killu
– Arun Killu, Commented Nov 10, 2014 at 7:26

Quentin · Accepted Answer · 2014-11-10 07:23:44Z

1

$_POST reads data that has been submitted in the request. The values of your inputs will not be available there until after the page has been sent to the browser and a new page has been requested by the submission of a form (with method="post") or some other technique to make an HTTP request (e.g. Ajax) has been used.

answered Nov 10, 2014 at 7:23

community wiki

Quentin

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Comments

Gaurav Jain · Accepted Answer · 2014-11-10 07:27:53Z

1

you can use this.

 <?php

 if(isset($_POST['submit'])){

$SERVER_IP = $_POST['checkip'];
$SERVER_PORT = $_POST['checkport'];
echo "server ip is:" .$SERVER_IP;
 }

  ?>

<form method="post" action="">
<input id="checkip" name="checkip" value="217.198.136.31">
<input id="checkport" name="checkport" value="25565">
<input type="submit" value="submit" name="submit"/>
</form>

answered Nov 10, 2014 at 7:27

Gaurav Jain

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Comments

mech · Accepted Answer · 2014-11-10 07:28:46Z

0

<input id="checkip" name="checkip" value="217.198.136.31">

is a html-input-element belonging to a FORM, when this form is beeing sent, the target gets the form-fields and these are accessible by $_POST ... but only if the method of the form is POST

example:

<html>
<Body>
<?php
if(isset($_POST['test'])) echo $_POST['test'];
?>
<form action='?' method='post'>
<Input Name='test' value='123'>
<button type='submit'>Send</button>
</form>
</html>

Keep in mind, that php is executed on Server, BEFORE Any form element gets evaluated by the Clients browser

edited Nov 10, 2014 at 7:28

answered Nov 10, 2014 at 7:23

mech

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Comments

ermac · Accepted Answer · 2014-11-10 07:30:28Z

0

the problem is your not passing the value, the input type field must used inside a form example:

<form method=POST>
 <input id="checkip" name="checkip" value="217.198.136.31">
<input id="checkport" name="checkport" value="25565">
<input type="submit" value="Submit" />
</form>

cheers !

answered Nov 10, 2014 at 7:30

ermac

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Comments

Pupil · Accepted Answer · 2014-11-10 07:33:32Z

0

Please make sure that you are actually posting your form.

$_POST will get values only if the form is posted with method="post".

Otherwise, your code seems fine.

Hope it works.

answered Nov 10, 2014 at 7:33

Pupil

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