PHP variable reference puzzle

Question

run following code:

<?php
$a = array('yes');
$a[] = $a;
var_dump($a);

out put:

array(2) {
  [0]=>
  string(3) "yes"
  [1]=>
  array(1) {
    [0]=>
    string(3) "yes"
  }
}

run following code:

<?php
$a = array('no');
$b = &$a;
$a[] = $b;
$a = array('yes');
$a[] = $a;
var_dump($a);

out put:

array(2) {
  [0]=>
  string(3) "yes"
  [1]=>
  array(2) {
    [0]=>
    string(3) "yes"
    [1]=>
    *RECURSION*
  }
}

I have reassigned value of $a, why there are RECURSION circular references?

Wow, something interesting on stackoverflow! :). +1!!!

Jacek Kowalewski
– Jacek Kowalewski

2014-11-12 07:59:19 +00:00
Commented Nov 12, 2014 at 7:59 — Jacek Kowalewski
– Jacek Kowalewski, Commented Nov 12, 2014 at 7:59

sectus · Accepted Answer · 2014-11-12 08:37:14Z

3

To remove reference you need to call unset. Without unset after $a = array('yes'); $a still bounds with $b and they are still references. So the second part has the same behavior as first one.

Note, however, that references inside arrays are potentially dangerous. Doing a normal (not by reference) assignment with a reference on the right side does not turn the left side into a reference, but references inside arrays are preserved in these normal assignments.

http://php.net/manual/en/language.references.whatdo.php

edited Nov 12, 2014 at 8:37

answered Nov 12, 2014 at 8:16

sectus

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