I need help; I have an array like this:
myarray = ["nonsense","goodpart","nonsense2","goodpar2t","nonsense3","goodpart3",]
I need to delete all "nonsense" part from array.
Nonsense always have an even index.
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2 Answers
I'd suggest, on the basis that 'nonsense' words are always (as stated in the question) the 'even' elements:
var myarray = ["nonsense", "goodpart", "nonsense2", "goodpar2t", "nonsense3", "goodpart3"],
filtered = myarray.filter(function(el, index) {
// normally even numbers have the feature that number % 2 === 0;
// JavaScript is, however, zero-based, so want those elements with a modulo of 1:
return index % 2 === 1;
});
console.log(filtered); // ["goodpart", "goodpar2t", "goodpart3"]If, however, you wanted to filter by the array-elements themselves, to remove all words that contain the word 'nonsense':
var myarray = ["nonsense", "goodpart", "nonsense2", "goodpar2t", "nonsense3", "goodpart3"],
filtered = myarray.filter(function(el) {
// an indexOf() equal to -1 means the passed-in string was not found:
return el.indexOf('nonsense') === -1;
});
console.log(filtered); // ["goodpart", "goodpar2t", "goodpart3"]Or to find, and keep, only those words that begin with 'good':
var myarray = ["nonsense", "goodpart", "nonsense2", "goodpar2t", "nonsense3", "goodpart3"],
filtered = myarray.filter(function(el) {
// here we test the word ('el') against the regular expression,
// ^good meaning a string of 'good' that appears at the beginning of the
// string:
return (/^good/).test(el);
});
console.log(filtered); // ["goodpart", "goodpar2t", "goodpart3"]References:
2 Comments
PeterKA
Mmmmm ... now I understand why the cough ... interesting! :)
David Thomas
Sorry, I just realised I'd not illustrated any other (potentially practical/relevant) approaches. I was presumably updating as you were composing your own answer. Still, that's no reason not to upvote :)
This is just a slight variation to @DavidThomas's great answer (+1). This will be helpful in case you decide to exclude array members by value (nonsense) instead of by position (odd):
var myarray = ["nonsense", "goodpart", "nonsense2", "goodpar2t", "nonsense3", "goodpart3"],
filtered = myarray.filter(function(el) {
//return only values that do not contain 'nonsense'
return el.indexOf('nonsense') === -1;
});
var myarray = ["nonsense", "goodpart", "nonsense2", "goodpar2t", "nonsense3", "goodpart3"],
filtered = myarray.filter(function(el) {
//return only values that do not contain 'nonsense'
return el.indexOf('nonsense') === -1;
});
//output result
$('pre.out').text( JSON.stringify( filtered ) );<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<pre class="out"></div>