First of all, I searched a lot to avoid asking a duplicate question. If there is one, I will delete this question immediately.
All the solutions on the web are suggesting to use Process.StartInfo like this one
How To: Execute command line in C#, get STD OUT results
I don't want to run a batch file, or an .exe.
I just want to run some commands on cmd like
msg /server:192.168.2.1 console "foo"
or
ping 192.168.2.1
and return the result if there is one.
How can I do that ?
Those commands are still exe files, you just need to know where they are. For example:
c:\windows\system32\msg.exe /server:192.168.2.1 console "foo"
c:\windows\system32\ping.exe 192.168.2.1
The only proper way to do this is to use Process.Start. This is demonstrated adequately in this question, which is itself a duplicate of two others.
However, as DavidG says, the commands are all exe files and you can run them as such.
Apparently, i found an answer
while (true)
{
Console.WriteLine("Komut giriniz.");
string komut = Console.ReadLine();
System.Diagnostics.Process process = new System.Diagnostics.Process();
System.Diagnostics.ProcessStartInfo startInfo = new System.Diagnostics.ProcessStartInfo();
//startInfo.WindowStyle = System.Diagnostics.ProcessWindowStyle.Hidden;
startInfo.FileName = "cmd.exe";
startInfo.Arguments = "/C" + komut;
startInfo.RedirectStandardOutput = true;
startInfo.UseShellExecute = false;
process.StartInfo = startInfo;
Console.WriteLine(process.Start());
string line = "";
while (!process.StandardOutput.EndOfStream)
{
line = line + System.Environment.NewLine + process.StandardOutput.ReadLine();
// do something with line
}
Console.WriteLine(line);
Console.ReadLine();
}
seems like if you can run cmd.exe with arguments including your command.
thanks for contributing.
