Reading into directory, unix shell script

Question

I am trying to analyze the files/directories inside of a directory using a shell script, for example if the file is readable, if it is a file, if it is a directory, etc. My script is set up to take a directory as input. so I would type 'file.sh directoryname'. However, when I create a for loop to analyze the files, it analyzes the files in my current working directory rather than the specified directory name.

This is my broken code:

file=$1
set mypath = $file
for file in $mypath *
do

if [ -d $file ]
  dirCount=`expr $dirCount + 1`
fi

done

Why does this read the working directory instead of the specified directory? Any help is appreciated. Thanks

Alternatively, you could always do this: find dirname -type f -maxdepth 1 — Jonathan Holloway
– Jonathan Holloway, Commented Apr 24, 2010 at 0:15

Jonathan Holloway · Accepted Answer · 2010-04-24 00:08:14Z

1

I think you have an error here:

set mypath = $file

Just do

mypath = $file

and that should work out just fine.

answered Apr 24, 2010 at 0:08

Jonathan Holloway

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Comments

vishal · Accepted Answer · 2012-07-18 11:36:32Z

1

# check this one     
file=$1
mypath=$file
dirCount=0
#ls $file
for file in `ls $mypath`
do
file=./$mypath/$file
#a=`ls -l $file`
echo $a
if [ -d $file ]
then
  dirCount=`expr $dirCount + 1` #increment count
        echo $dirCount
fi
done

#if count value is grater than 1 then only print value
if [ $dirCount -ne 0 ]
then
echo -e "\ncount is $dirCount    $$"
fi

answered Jul 18, 2012 at 11:36

vishal

111 bronze badge

Comments

Sylar · Accepted Answer · 2013-06-11 07:15:02Z

0

you can try this. but the script will go into issue when the folder name have blank space.

#/bin/bash
path=$1
for file in $path/*
do
if [ -d $file ];then
  dirCount=`expr $dirCount + 1`
fi
done
echo $dirCount

answered Jun 11, 2013 at 7:15

Sylar

11 bronze badge

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