Regex Matcher Ruby

Question

I am new to the Language.

I am trying to extract all characters till the escape character (\r).

I tried

text = "abcde\r"

text.match(/(.*)(\r)/)

I tried the same with gsub and gsub!. None are working.

\r isn't "the escape character", it's "an escaped character". Terminology is important. — the Tin Man
– the Tin Man, Commented Nov 21, 2014 at 20:58

the Tin Man · Accepted Answer · 2014-11-21 20:59:32Z

2

If you happen to be dealing with the specific case of lines from a file, and you want to remove the line ending, you can use chop or chomp. For example:

require 'pp'

lines = [
  "hello",
  "there\r",
  "how\r\n",
  "are you?"
]

lines.each do |line|
  pp line
  pp line.chomp
  puts '---'
end

Results in:

"hello"
"hello"
---
"there\r"
"there"
---
"how\r\n"
"how"
---
"are you?"
"are you?"
---

edited Nov 21, 2014 at 20:59

the Tin Man

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answered Nov 21, 2014 at 20:41

Brian Adkins

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1 Comment

the Tin Man Over a year ago

Be careful using chop as it indiscriminately removes the last character: 'foo'.chop # => "fo". Both rstrip and chomp are the most used ways to do this.

Simone Carletti · Accepted Answer · 2014-11-21 18:45:19Z

0

You can use String#slice passing the regular expression and the match to get. The 1 represents the first (and in this case the only) match.

text = "abcde\r"
text.slice(/(.*)\r/, 1)
 => "abcde"

answered Nov 21, 2014 at 18:45

Simone Carletti

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1 Comment

JmG Over a year ago

Thank you! Looks like I had issue with the irb terminal. It wasn't printing the output.

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