Python Regular Expression Multiple Overlap Grouping

Question

a = 'foo<99>bar'
match = re.findall(r'(<\d(\d)>)',a)

## match gives [('<99>', '9')] but I would to have ['<99','9>']

I tried to escape the '(' but, the regex engine takes it a literal '('

Kasravnd · Accepted Answer · 2014-11-23 20:34:58Z

1

You don't need grouping if you want that your output be ['<99','9>'] you can use pip:

r'<\d+|\d+>' .

answered Nov 23, 2014 at 20:34

Kasravnd

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Comments

alpha bravo · Accepted Answer · 2014-11-23 20:39:23Z

0

use this pattern

(?=(<\d+>))|(?=(\d>))

answered Nov 23, 2014 at 20:39

alpha bravo

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