How to check if a checkbox/ radio button is checked in php

Question

I have this html code:

<tr>   
     <td><label><input type="text" name="id" class="DEPENDS ON info BEING student" id="example">ID</label></td>
    </tr>

      <tr>
    <td>
   <label> <input type="checkbox" name="yr" class="DEPENDS ON info BEING student"> Year</label>
       </td>
    </tr>

But I don't have any idea on how do I check this checkboxes if they are checked using php, and then output the corresponding data based on the values that are checked.

Please help, I'm thinking of something like this. But of course it won't work, because I don't know how to equate checkboxes in php if they are checked:

<?php



$con = mysql_connect("localhost","root","nitoryolai123$%^");
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }

mysql_select_db("school", $con);




$id =  mysql_real_escape_string($_POST['idnum']);


if($_POST['id'] == checked &  $_POST['yr'] ==checked ){
$result2 = mysql_query("SELECT * FROM student WHERE IDNO='$id'");


echo "<table border='1'>
<tr>
<th>IDNO</th>
<th>YEAR</th>



</tr>";

while($row = mysql_fetch_array($result2))
  {
   echo "<tr>";
   echo "<td>" . $row['IDNO'] . "</td>";
echo "<td>" . $row['YEAR'] . "</td>";


  echo "</tr>";
  }
echo "</table>";
}


mysql_close($con);
?>

Is this your real password? I hope not :)

ZeissS
– ZeissS

2010-04-26 09:25:01 +00:00
Commented Apr 26, 2010 at 9:25 — ZeissS
– ZeissS, Commented Apr 26, 2010 at 9:25

ZeissS · Accepted Answer · 2010-04-26 09:17:19Z

3

You must give your checkboxes a value. This value gets send to the server, in case the checkbox is checked.

if ( $_POST['checkboxname'] == 'checkboxvalue' ) {

}

Since I see no form: To send the data to the server, you need a form around your input elements:

<form method="POST" action="myphpscript.php">
    YOUR CONTENT HERE
</form>

answered Apr 26, 2010 at 9:17

ZeissS

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Comments

Elie · Accepted Answer · 2010-04-26 09:14:07Z

1

try the following:

if (isset($_POST['yr'])) { ... }

answered Apr 26, 2010 at 9:14

Elie

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Comments

zaf · Accepted Answer · 2010-04-26 09:24:46Z

1

$_POST['yr'] == checked

should be:

$_POST['yr'] == 'on'

The default for firefox is 'on', maybe different in other browsers. (Thanks to David)

edited Apr 26, 2010 at 9:24

answered Apr 26, 2010 at 9:13

zaf

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1 Comment

Quentin Over a year ago

It shouldn't, the value of the input is not "checked". Since it isn't set, it will be whatever the browser defaults to ('On' IIRC, but its always better to set it explicitly)

j0k · Accepted Answer · 2012-10-05 07:13:08Z

0

If you include a hidden field, with the same name and the failure value that you want to show up in the post data, then when the checkbox does not return a value (it is unchecked), the hidden control on the form will.

echo '<form method="post"><input type="hidden" name="checkdata" value="0">\
    <input type="checkbox" name="checkdata" value="1">\
    <input name="submitbutton" type="submit"></form>\
    </body></html>';

if ($_POST['submitbutton']) {
    echo "Value:|".$_POST['checkdata']."|";
}

edited Oct 5, 2012 at 7:13

j0k

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answered Aug 3, 2012 at 7:12

AmmO

1

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