I'm looking for the shortest ruby equivalent of this Python snippet
a, b, c, d = map(int, raw_input().split(" "))
is there anything shorter than this?
a, b, c, d = gets.split(" ").map &:to_i
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2 Answers
Without argument, String#split split the string on whitespaces ($;):
"1 2 3 4\n".split
# => ["1", "2", "3", "4"]
In other word, you don't need to call chomp to remove trailing newline:
a, b, c, d = gets.split.map &:to_i
str.split of Python is similar (no need to specify argument):
>>> "1 2 3 4\n".split()
['1', '2', '3', '4']
Comments
The default value for the split pattern is $;, and the default value for $; is nil. A pattern of nil means "split on whitespace", which is not 100% equivalent to what you have (which is "split on a single space character"), but if you can live with that, then you can shorten your expression to:
a, b, c, d = gets.split.map &:to_i
