How to concatenate string continuously in php?

Question

<?php

    $test = ' /clothing/men/tees';

    $req_url = explode('/', $test);

    $c = count($req_url);

    $ex_url = 'http://www.test.com/';

    for($i=1; $c > $i; $i++){

        echo '/'.'<a href="'.$ex_url.'/'.$req_url[$i].'">

                <span>'.ucfirst($req_url[$i]).'</span>

            </a>';
        //echo '<br/>'.$ex_url;....//last line
    }
?>

OUTPUT - 1 //when comment last line

/ Clothing / Men / Tees

OUTPUT - 2 //when un-comment last line $ex_url shows

/ Clothing 
http://www.test.com// Men 
http://www.test.com// Tees 
http://www.test.com/

1. Required output -

In span - / Clothing / Men / Tees and last element should not be clickable

and link should created in this way

http://www.test.com/clothing/Men/tees -- when click on Tees

http://www.test.com/clothing/Men --  when click on Men

...respectively

2. OUTPUT 2 why it comes like that

Output 1 does not work?

Marco Mura
– Marco Mura

2014-12-02 08:22:04 +00:00
Commented Dec 2, 2014 at 8:22 — Marco Mura
– Marco Mura, Commented Dec 2, 2014 at 8:22
An array starts at 0 not at 1

Naruto
– Naruto

2014-12-02 08:22:16 +00:00
Commented Dec 2, 2014 at 8:22 — Naruto
– Naruto, Commented Dec 2, 2014 at 8:22
@Naruto The string starts with a slash as well...

RichardBernards
– RichardBernards

2014-12-02 08:24:50 +00:00
Commented Dec 2, 2014 at 8:24 — RichardBernards
– RichardBernards, Commented Dec 2, 2014 at 8:24
@Naruto i know that. but in my case $req_url[0] is blank.

Prashant Tapase
– Prashant Tapase

2014-12-02 09:02:48 +00:00
Commented Dec 2, 2014 at 9:02 — Prashant Tapase
– Prashant Tapase, Commented Dec 2, 2014 at 9:02

Sunil Kumar · Accepted Answer · 2014-12-02 08:47:47Z

2

Try this:

   <?php
    $test = '/clothing/men/tees';
    $url = 'http://www.test.com';
    foreach(preg_split('!/!', $test, -1,  PREG_SPLIT_NO_EMPTY) as $e) {
    $url .= '/'.$e;
        echo '/<a href="'.$url.'"><span>'.ucfirst($e).'</span></a>';
    }
    ?>

Output:

/Clothing/Men/Tees

HTML output:

/<a href="http://www.test.com/clothing"><span>Clothing</span></a>/<a href="http://www.test.com/clothing/men"><span>Men</span></a>/<a href="http://www.test.com/clothing/men/tees"><span>Tees</span></a>

answered Dec 2, 2014 at 8:47

Sunil Kumar

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8 Comments

Prashant Tapase Over a year ago

thanks..can u explain your code? whats wrong when i comment last line?

Sunil Kumar Over a year ago

@Prashant I'm not an expert but I know something about HTML DOM structure, whenever you want to display elements inline, close to each other, you should render them inline only. Like <a>1</a><a>2</a>. You cann't use <br> tag, this is use for breaking line

Prashant Tapase Over a year ago

preg_split('!/!', $test, -1, PREG_SPLIT_NO_EMPTY) explain this

Sunil Kumar Over a year ago

@Prashant preg_split — Split string by a regular expression, '!/!' pattern to search for, you can also use '/\//', $test - your string, -1 - Limit (-1, 0, NULL No Limit), PREG_SPLIT_NO_EMPTY - return only non-empty For more information you should visit real source docs.php.net/preg_split

Prashant Tapase Over a year ago

i have ' /clothing/men/tees/' this. output i got home /clothing/men . i dont want space before clothing

|

RichardBernards · Accepted Answer · 2014-12-02 09:32:48Z

1

Try using foreach() to iterate the array and you'll have to keep track of the path after the url. Try it like so (tested and working code):

<?php

    $test = '/clothing/men/tees';
    $ex_url = 'http://www.test.com';
    $items = explode('/', $test);
    array_shift($items);

    $path = '';
    foreach($items as $item) {
        $path .= '/' . $item;
        echo '/ <a href="' . $ex_url . $path . '"><span>' . ucfirst($item) . '</span></a>';
    }

edited Dec 2, 2014 at 9:32

answered Dec 2, 2014 at 8:32

RichardBernards

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Comments

alu · Accepted Answer · 2014-12-03 00:11:32Z

1

Try this.

<?php

$test = '/clothing/men/tees';
$req_url = explode('/', ltrim($test, '/'));
$ex_url = 'http://www.test.com/';

$stack = array();
$reuslt = array_map(function($part) use($ex_url, &$stack) {
    $stack[] = $part;
    return sprintf('<a href="%s%s">%s</a>', $ex_url, implode('/', $stack), ucfirst($part));
}, $req_url);


print_r($reuslt);

edited Dec 3, 2014 at 0:11

answered Dec 2, 2014 at 8:41

alu

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1 Comment

Prashant Tapase Over a year ago

your code show error Message : syntax error, unexpected '['

AmigoJack · Accepted Answer · 2014-12-02 08:32:12Z

-1

<?php
    $sTest= '/clothing/men/tees';
    $aUri= explode( '/', $sTest );
    $sBase= 'http://www.test.com';  // No trailing slash

    $sPath= $sBase;  // Will grow per loop iteration
    foreach( $aUri as $sDir ) {
        $sPath.= '/'. $sDir;
        echo ' / <a href="'. $sPath.'">'. ucfirst( $sDir ). '</a>';  // Unnecessary <span>
    }
?>

answered Dec 2, 2014 at 8:32

AmigoJack

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