How to use select with awk in bash script?

Question

I have to write a bash script for university, the text says:

Write a bash script that allows root user, to get a list of all users of the machine. Selecting a user, using select, will be required to indicate a directory (indicate the absolute path). At this point in the output will have be shown a list of all files folder owned by the user, ranked in ascending order according to the size of file.

To check if the user is root i used:

if[ "$(id -u)" = 0 ]; then

To get the list of users of the machine I was thinking of using awk:

awk -F':' '{ print$1}' /etc/passwd

How can I use select with awk? Is there another way without using awk?

Thank you so much in advance

You can use cut in much the same way, but I think your problem with the select won't go away by that. The way I interret the statement is that you're supposed to present a list of users, read some input, and then respond to that. — tink
– tink, Commented Dec 6, 2014 at 3:02

BMW · Accepted Answer · 2014-12-06 03:50:59Z

2

Here is the way to use awk in select statement, you need finish the rest for your homework (for example, sort the result)

#!/usr/bin/env bash

select user in $(awk -F ":" '{print $1}' /etc/passwd )
do
  read -p "input the absolute directory: " path
  find $path -type f -user "$user" -ls 
done

answered Dec 6, 2014 at 3:50

BMW

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Gilles Quénot · Accepted Answer · 2014-12-06 04:53:25Z

0

Another way to test the UID by arithmetic (smarter!?) is :

if((UID==0)); then
    ...
else
    ...
fi

Check http://wiki.bash-hackers.org/syntax/arith_expr

answered Dec 6, 2014 at 4:53

Gilles Quénot

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