Java Regex any numbers separated by a character and terminated with a number

Question

I need to have a pattern to match the following strings

564 A 456
10 O 94 A 465 
234 A 654 O 1 
3 A 5697 O 68998 A 89789 A 665 
2 A 5646 A 123 A 123 
231 O 645 O 4565 O 564

Translation would...

Any number with any length (1 to *)

Followed by a space

Followed by any number with any length (1 to *)

Follwed by A or B

For example the following test would not be valid

A 465 //not begin with a number
564 AO 5645 //only A or O should appear Not both!
4564 A //not end in number
987 T 213 //invalid character T
1456 456 A 56 //invalid whitespace in first number
987 O 321654 987 //invalid whitespace in last number
12 A 456 O 132 A //not end in a number

At this moment i have this pattern \d+\s((A|O)\s\d+)*

But does not recognize all my valid string

Is string like "123" valid (it doesn't have letter and number after it)? — Pshemo
– Pshemo, Commented Dec 9, 2014 at 0:18
Your input doesn't match you description: number space number (A or B). — rendon
– rendon, Commented Dec 9, 2014 at 0:18

Pshemo · Accepted Answer · 2014-12-09 00:24:51Z

2

So you want to accept number (\d+ - one or more digits) which can be followed by one or more of
(A or O) number.

In that case your regex can look like \d+(\s[AO]\s\d+)+
but since \ is special in String its literal needs to be written as "\\d+(\\s[AO]\\s\\d+)+".

BTW, some of your lines in your example of valid strings ends with space so either trim this data before validation, or add \s? at the end of regex to also include this space.

edited Dec 9, 2014 at 0:24

answered Dec 9, 2014 at 0:10

Pshemo

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1 Comment

jasilva Over a year ago

Thanks!! this pattern match all my tests.

kamino · Accepted Answer · 2014-12-09 00:14:54Z

0

You just need to include the space into the parenthesis, like this:

\d+(\s(A|O)\s\d+)*

And that should work like a charm!

answered Dec 9, 2014 at 0:14

kamino

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