Call a class by string PHP

Question

I'm calling a class by a string variable passed on a function argument.

ApiTester.php

   use MyApp\Sites\Site;

   abstract class ApiTester extends TestCase() {

   /**
     * Make a new record in the DB
     * 
     * @param $type
     * @param array $fields
     * @throws BadMethodCallException
     */
    protected function make($type, array $fields = [])
    {
        while($this->times--)
        {
            $stub = array_merge($this->getStub(), $fields);

            $type::create($stub);
        }


    }

SitesTester.php

class SitesTester extends ApiTester() {

/** @test */
public function it_fetches_a_single_site()
{
    // arrange
    $this->make('Site');

    // act
    $site = $this->getJson('api/v1/sites/1')->data;

    // assertion
    $this->assertResponseOk();

    $this->assertObjectHasAttributes($site, 'name', 'address');
}

Site.php // Eloquent Model

namespace MyApp\Sites;

class Site extends \Eloquent {

}

But if I call the class that the string variable $type contains, for example; string variable $type contains 'Site', it says class 'Site' not found.

I tried to manually type Site::create($stub) and finally accepts it.

I also tried call_user_func($type::create(), $stub); and $model = new $type; $model->create($stub); but unfortunately it says class 'Site' not found.

Any ideas?

Maybe because you only have class SiteTester or are you not showing some code of yours? — Justinas
– Justinas, Commented Dec 12, 2014 at 8:44
What Justinas has pointed out is you are using the literal name of 'Site'. We do not see anything to do with that name in your code. We can see SitesTester.. but not Site. — Ne Ma
– Ne Ma, Commented Dec 12, 2014 at 9:04

georg · Accepted Answer · 2014-12-12 09:10:36Z

0

You're almost there:

class X {
    static function foo($arg) {
        return 'hi ' . $arg;
    }
};

$cls = 'X';

print call_user_func("$cls::foo", 'there');

If your php is very old (<5.3 I believe), you have to use an array instead:

print call_user_func(array($cls, "foo"), 'there');

edited Dec 12, 2014 at 9:10

answered Dec 12, 2014 at 9:05

georg

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2 Comments

Eduard Over a year ago

OP is looking for params too, so you migh be changing that answer to call_user_func_array. The PHP version thing is not relevant now because it's only related to class keywords like parent and self etc.

Chelsea Smile Over a year ago

@georg: I tried call_user_func("$type::create", $stub); but it says call_user_func() expects parameter 1 to be a valid callback

Eduard · Accepted Answer · 2014-12-12 09:23:30Z

0

You may want to replace that static class call with the following :

        while( $this->times-- )
        {
            $stub = array_merge( $this->getStub(), $fields );

            call_user_func( "$type::create",  $stub );
        }

Runnable code here : http://runnable.com/VIqy4CDePeY-AeMV/output

edited Dec 12, 2014 at 9:23

answered Dec 12, 2014 at 9:06

Eduard

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1 Comment

Chelsea Smile Over a year ago

I think laravel is looking eloquent models in app\models folder even though I already require the eloquent classes at the ApiTester class. So, I move my Site.php file into app\models directory from MyApp\Sites directory. And I just use the $type::create($stub); and it worked. So I think the problem is if you call a eloquent class via string variable, it looks at the app\models directory.

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