calling a function from $interval in angularjs

Question

I wanted to call a function from $interval's timeout.

angular.module('myApp').factory('myFactory',function($interval){

    var stop;
    return{
        start : function() {
            if(angular.isUndefined(stop)){
                stop = $interval(function() {
                        function1();
                    }
                    ,  30000);
            }
        },

        function1 : function() {
            console.log('In function1');
            function2();
        },

        function2 : function() {
            console.log('In function2');
        }

    }
});

error I am getting is

TypeError: undefined is not a function

Please let me know what could be the reason and how to solve the same

Thanks, ng-R

sylwester · Accepted Answer · 2014-12-23 09:43:50Z

3

My advise it move definition of your functions outside return object please see demo below

var app = angular.module('app', []);
angular.module('app').factory('myFactory', function($interval) {

  function start() {
    $interval(function() {
      function1();
    }, 3000);
  }


  function function1() {
    console.log('In function1');
    function2();
  }

  function function2() {
    console.log('In function2');
  }




  return {
    start: start,
    function1: function1,
    function2: function2
  };
});
app.controller('homeCtrl', function($scope, myFactory) {



  myFactory.start();


});

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>

<body>
  <div ng-app="app">
    <div ng-controller="homeCtrl">


    </div>
  </div>
</body>

answered Dec 23, 2014 at 9:43

sylwester

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1 Comment

Md. Mahbubul Haque Over a year ago

can you please explain why do we need to move definition of your functions outside return object? what would be the problem if we keep it in return object? @sylwester

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