Could someone explain to me why that is true?
in_array('', array(0,1,2));
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2 Answers
Because, as said in the docs:
bool in_array ( mixed $needle , array $haystack [, bool $strict = FALSE ] )Searches haystack for needle using loose comparison unless strict is set.
... and '' == 0 is true in PHP. If you want to use strict comparison, just call in_array() with three params:
in_array('', array(0, 1, 2), true); // false
... so the types will be checked as well, and String '' won't have a chance to match against Numbers.
1 Comment
haim770
Worth including this table as well: php.net/manual/en/…
in_array by default performs loose comparison. Thus '' is equivalent to 0.
There is third argument (boolean) to in_array function which says if the matching is to be performed in STRICT way or not.
if you do in_array('', array(0,1,2), TRUE); then the result will be false.
Refer the documentation
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