PHP get the file name without the parameters

Question

I have these urls

something2/something3/fileName.php

something2/something3/fileName.php?para=someting&param2=something2

I want to get the fileName without the .php extension and without the paramets,

note: not all the urls have parameters.

$phpFileName = basename($_SERVER['REQUEST_URI'], ".php");//without .php extension

that works only when there are no parameters in the urls, but when there are parameters in the url, i got like this:

fileName.php?parm=something&param=something

how can I remove these parameters please and get just the fileName ?

thanks

fire · Accepted Answer · 2014-12-29 16:26:08Z

2

Well if the code is in the file itself you can use...

$phpFileName = basename(__FILE__, ".php");

The __FILE__ is a magic constant to the current file being executed.

Otherwise just remove the query string using explode first...

$qs = explode("?", $_SERVER['REQUEST_URI']);
$phpFileName = basename($qs[0], ".php");

answered Dec 29, 2014 at 16:26

fire

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Comments

AbraCadaver · Accepted Answer · 2014-12-29 16:27:42Z

2

Get the path from the URL first with parse_url:

$phpFileName = basename(parse_url($_SERVER['REQUEST_URI'], PHP_PATH), ".php");

You could also look at pathinfo.

answered Dec 29, 2014 at 16:27

AbraCadaver

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