Getting specific numbers out of array

Question

So this is my array:

field = [[1, 2, 4, 4],
         [4, 1, 4, 2],
         [2, 1, 4, 3],
         [2, 4, 2, 3],
         [1, 2, 3, 4]]

and if i have following coordinates:

co= [(0, 1),
     (1, 1),
     (2, 1)]

In this case my new array should look like:

[[1, 4, 4],
 [4, 4, 2],
 [2, 4, 3],
 [2, 4, 2, 3],
 [1, 2, 3, 4]]

anyone has any idea how ? I have managed to get just numbers that have to be deleted but its not what i want.. Note: It has to be made for field array of x length and same with coordinates.

Thanks for help!

What exactly do the coordinates do? Specifically, what is the second number in the coordinate doing? — ryanyuyu
– ryanyuyu, Commented Dec 30, 2014 at 16:57
for (x, y) in co: del field[x][y] print(field) Gives : IndexError: list assignment index out of range — user3311120
– user3311120, Commented Dec 30, 2014 at 17:29
first number gives which row it is and the 2nd one is which column in that row So if it is 0,1 the number would be 2 — user3311120
– user3311120, Commented Dec 30, 2014 at 17:36

Reut Sharabani · Accepted Answer · 2014-12-30 17:44:12Z

1

Use this:

for c in sorted(co, reverse=True):
    field[c[0]].pop(c[1])

Or as @njzk2 suggested:

for (x, y) in sorted(co, reverse=True): del field[x][y]

Simply access the field list-of-lists in index c[0], which indicates what list is to be accessed.

Then pop the element from the sub-list in index c[1].

Result is now in field.

Note: I sort them in reversed order for the case you'll remove from the same list, so indices for previous elements don't change. For instance: (0, 3) should pop before (0, 1).

edited Dec 30, 2014 at 17:44

answered Dec 30, 2014 at 17:38

Reut Sharabani

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